Question

If a train (travelling from Albuquerque to Atlanta) is moving 33.9 meters per second when it accelerates at -2.02 m/s^2 for 1.01 seconds, what is the final velocity

Answer 1

Answer:

The final velocity is 31.86 m/s.

Explanation:

The final velocity can be found using the following equation:

$V_{f} = V_{0} + at$

Where:

$V_{f}$ is the final velocity =?

$V_{0}$ is the initial velocity = 33.9 m/s

a is the acceleration = -2.02 m/s²

t is the time = 1.01 s

$V_{f} = V_{0} + at = 33.9 m/s + (-2.02 m/s^{2})*1.01 s = 31.86 m/s$

Therefore, the final velocity is 31.86 m/s.

I hope it helps you!