Answer:
2 m/s
Explanation:
Momentum is conserved:
mv = MV
where m is mass of the boxcar, v is its initial velocity, M is the mass of all six box cars, and V is the final velocity.
v = 12 m/s, and M = 6m, so:
m (12 m/s) = 6m V
12 m/s = 6V
V = 2 m/s
You really can't tell.
Power = I^2 × R = V^2 / R ( unit in Watt)
For P = I^2 × R
Where we have P directly proportional to R, increase in Power leads to increase in R
So if we have 100 will have higher resistance
For P = V^2/R
Power is inversely proportional to resistance.
So increase in Power leads to decrease in resistance.
60 watt will have a higher resistance.
Yes. Even greater. Air resistance or drag becomes harder the faster an object goes. This is why when cars reach their max speed they don't accelerate as fast, because they are pushing harder against the wind. If I take a tennis ball and shoot it down a bottomless pit, a 400 kph, the drag will slow the ball down till it reaches terminal velocity.
Answer:
the planes times in the air
Explanation:
When a paper airplane is thown the path it takes is not the same every time. So, measuring the distance between the points where the airplane took off and the point where is landed would not show the time the plane was in the air.
The weight also does not determine the time the plane was in the air.
So, the planes air time recorded with the stopwatch gives the time the plane was in the air and will indicate the best plane.
Answer:
Δy= 5,075 10⁻⁶ m
Explanation:
The expression that describes the interference phenomenon is
d sin θ = (m + ½) λ
As the observation is on a distant screen
tan θ = y / x
tan θ= sin θ/cos θ
As in ethanes I will experience the separation of the vines is small and the distance to the big screen
tan θ = sin θ
Let's replace
d y / x = (m + ½) λ
The width of a bright stripe at the difference in distance
y₁ = (m + ½) λ x / d
m = 1
y₁ = 3/2 λ x / d
Let's use m = 1, we look for the following interference,
m = 2
y₂ = (2+ ½) λ x / d
The distance to the screen is constant x₁ = x₂ = x₀
The width of the bright stripe is
Δy = λ x / d (5/2 -3/2)
Δy = 630 10⁻⁹ 2.90 /0.360 10⁻³ (1)
Δy= 5,075 10⁻⁶ m
