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3 years ago

What are used to measure temperature.

Physics

2 answers:

Tatiana [17]3 years ago

7 0

A thermometer everyone knows this

V125BC [204]3 years ago

4 0

Answer:

A thermometer is an instrument that measures temperature.

Explanation:

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Normal atmospheric pressure at sea level is ?

iris [78.8K]

1 bar or 100 000 pascales. Or 1020 hPa. It kinda differentiates.

5 0

3 years ago

All of the planets stay near the ecliptic as they move on the Celestial Sphere

stellarik [79]

Answer:

True

Explanation:

As the Earth goes around the Sun, it will appear that Earth is stationary and Sun is going around it. One can observe the same in real life as well. This apparent path followed by the Sun is called Ecliptic. The plane consisting Ecliptic is called as Ecliptic plane which is same as the orbital plane of Earth.

All the planets of the Solar system are also going around the Sun. Their orbital plane has negligible tilt with respect to Ecliptic plane. Due to this the planets will always appear near to the Ecliptic as they move on the celestial sphere.

3 0

3 years ago

Why do buildings on permafrost have potential structural issues?

Veronika [31]

I believe that the answer to the question provided above is that the <span>buildings on permafrost have potential structural issues because the soil is not stable in this area.</span>
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

8 0

3 years ago

Read 2 more answers

How can you prove that acceleration is a derived unit

Aliun [14]

a = (dx / dt)²

Explanation: Unit of distance is m (metres) and unit of time is s (seconds) speed v is first derivative of distance x versus time:

v = dx / dt, unit is m/s. Acceleration is second derivative of

speed versus time a = (dx / dt)² = (dv/dt) , unit is m/s²

7 0

3 years ago

Read 2 more answers

Using dimensional analysis, construct a constant, with units of length only, out of all three of the following fundamental const

ludmilkaskok [199]

The quantity with units of length only is $\sqrt{\frac{hG}{c^3}}$

Explanation:

We have to combine the following constants:

- $h$ , Planck constant, with units $[m^2][kg][s^{-1}]$

- G, the Newton's gravitational constant, with units $[m^3][kg^{-1}][s^{-2}]$

- $c$ , the speed of light, with units $[m][s^{-1}]$

The combination of these constant should have units of length only, so with meters (m).

First, we notice that $h$ has [kg] in its units, while G has $[kg^{-1}]$ in its units, so in order to make the [kg] disappear, we have to multiply them and they should have same power, so:

$hG = [m^{2+3}][kg^{1-1}][s^{-1-2}]=[m^5][s^{-3}]$

Now we have to make the seconds, [s], disappear. We do that by dividing the new quantity by $c^3$ , so that the new units are:

$\frac{hG}{c^3}=\frac{[m^5][s^{-3}]}{([m][s^{-1}])^3}=\frac{[m^5][s^{-3}]}{[m^3][s^{-3}]}=[m^2]$

We are almost done: now the quantity has units of an area, squared meters. Therefore, in order to make it have it units of length, we just take its square root:

$\sqrt{\frac{hG}{c^3}}=\sqrt{[m^2]}=[m]$

Learn more about gravitational constant:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

4 0

3 years ago