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Crank
3 years ago
10

I need help please and thank you

Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer:

2.72 x 10^4

Step-by-step explanation:

2.4 x 10^4

= 24000

3.2 x 10^3

= 3200

Therefore,

(2.4 x 10^4) + (3.2 x 10^3)

= 24000 + 3200

= 27200

= 2.72 x 10^4

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How to find 4x=14y and if it is parallel, perpendicular or neither to -2x+7y=14
RUDIKE [14]
4x = 14y
y = 4/14(x)
y = 2/7(x) slope = 2/7

<span>-2x+7y=14
7y = 2x + 14
  y = 2/7(x) + 2 slope = 2/7

parallel lines, slope is the same
both lines have slopes equal 2/7

answer
</span><span>parallel</span>
7 0
3 years ago
Use technology and the given confidence level and sample data to find the confidence interval for the population mean mu. Assume
Sphinxa [80]

Answer: (1.55, 6.45)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\overline\ {x}\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : \alpha: 1-0.99=0.01

Critical value : z_{\alpha/2}=2.576

Sample size : n=41

Sample mean : \overline{x}=4.0\text{ kg}

Standard deviation : \sigma=6.1\text{ kg}

Then, 99% confidence interval for population mean will be :_

4\pm\ (2.576)\dfrac{6.1}{\sqrt{41}}\\\\\approx4\pm2.45\\\\=(4-2.45, 4+2.45)=(1.55, 6.45)

8 0
4 years ago
What is algebraic expression for the difference of 2 and the product of 3 and k
krek1111 [17]
I'm sure the correct answer is 3k-2
5 0
3 years ago
How was this answered? i don't know how, pls. help​
ratelena [41]

Answer:

see explanation

Step-by-step explanation:

Using \sqrt{-1} = i, then i² = (\sqrt{-1} )² = - 1

and i³ = i² × i = - 1 × i = - i

also

i^{4} = i² × i² = - 1 × - 1 = 1

We can surmise that i raised to any multiple of 4 will equal 1

Given

i^{35} ( note 35 = 32 + 3 and 32 is a multiple of 4 ), thus

= i^{32+3}

= 1 × i³ = - i

3 0
3 years ago
How many distinct pairs of disjoint non-empty subsets of A are there, the union of which is all of A?
Mrac [35]
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8} 
{2} U {1, 5, 6, 8} 
{5} U {1, 2, 6, 8} 
{6} U {1, 2, 5, 8} 
{8} U {1, 2, 5, 6} 
{1, 2} U {5, 6, 8} 
{1, 5} U {2, 6, 8} 
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6} 
{1, 2, 5} U {6, 8} 
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5} 
The answer is 15 distinct pairs of disjoint non-empty subsets.
5 0
3 years ago
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