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Crank
3 years ago
10

I need help please and thank you

Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer:

2.72 x 10^4

Step-by-step explanation:

2.4 x 10^4

= 24000

3.2 x 10^3

= 3200

Therefore,

(2.4 x 10^4) + (3.2 x 10^3)

= 24000 + 3200

= 27200

= 2.72 x 10^4

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Find the measures of the missing angles
rodikova [14]
2,7, and 6 are all 70 degrees. 1,4,5, and 8 are all 110 degress
7 0
3 years ago
The average of 5 consecutive multiples of 5 is 20 what is the largest of these numbers
vlada-n [284]

Answer:

Step-by-step explanation:

5 consecutive multiples of 5....

x , x + 5, x + 10, x + 15, x + 20

the average is 20...

(x + x + 5  x + 10 + x + 15 + x + 20) / 5 = 20

(5x + 50) / 5 = 20

5x + 50 = 20 * 5

5x + 50 = 100

5x = 100 - 50

5x = 50

x = 50/5

x = 10......smallest number

x + 5 = 10 + 5 = 15

x + 10 = 10 + 10 = 20

x + 15 = 10 + 15 = 25

x + 20 = 10 + 20 = 30 <=== largest number

4 0
4 years ago
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
The mean age of Lincoln's tee-ball team is 5. Suppose one of his 7-year-old teammates quits the team, but a 6-year-old joins the
aleksandrvk [35]

Answer:

Depending on the amount of children in the tee ball team, the mean may be lowered drastically or minorly. However, the mean would no longer be 5, although it may round up to five, if it is a decimal.

Step-by-step explanation:

Hope that helps, I didn’t do a very good job of explaining that question. But the answer is no.

6 0
3 years ago
Read 2 more answers
Which expressions are equivalent to StartFraction 1 Over 36 EndFraction? Check all that apply. 3 Superscript negative 6 6 Supers
Elenna [48]

Answer:

6^-2

6^3/6^5

6^-9 *6^ 7

Step-by-step explanation:

We want the fractions equal to 1/36

We know that a^-b = 1/a^b

We also know that a^b / a^c = a^(b-c)

We also know that a^b * a^c = a^(b+c)

3^ -6 = 1/3^6 = 1/729

6^-2 = 1/6^2 = 1/36

6^3/6^5 = 6^(3-5) = 6^-2 = 1/6^2 = 1/36

6^2 / 6^-1 = 6^(2- -1) = 6^3 = 216

6*6^-2 = 6^(1-2) = 6^-1 = 1/6

6^-9 *6^ 7 = 6^(-9+7) = 6^ -2 = 1/6^2 = 1/36

5 0
3 years ago
Read 2 more answers
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