How many grams of potassium chloride (KCl) can be produced from 180.6 g of chlorine (Cl2)?

Chemistry

1 answer:

GalinKa [24]3 years ago

3 0

Answer:

379.79 g of KCl

Explanation:

The balanced equation for the reaction is given below:

Cl₂ + 2KBr —> Br₂ + 2KCl

Next, we shall determine the mass of Cl₂ that reacted and the mass of KCl produced from the balanced equation. This can be obtained as follow:

Molar mass of Cl₂ = 70.90 g/mol

Mass of Cl₂ from the balanced equation = 1 × 70.90 = 70.90 g

Molar mass of KCl = 74.55 g/mol

Mass of KCl from the balanced equation = 2 × 74.55 = 149.1 g

SUMMARY:

From the balanced equation above,

70.90 g of Cl₂ reacted to produce 149.1 g of KCl.

Finally, we shall determine the mass of KCl produced by the reaction of 180.6 g of Cl₂. This can be obtained as follow:

From the balanced equation above,

70.90 g of Cl₂ reacted to produce 149.1 g of KCl.

Therefore, 180.6 g of Cl₂ will react to produce = (180.6 × 149.1)/70.90 = 379.79 g of KCl.

Thus, 379.79 g of KCl were obtained from the reaction.

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