Answer:
Ceiling fan
Explanation:
Ceiling fan is a perfect and typical example of electrical energy being converted to mechanical energy.
In most systems, energy is usually transformed from one form to another. Energy is not created neither is it destroyed. We know this by virtue of law of conservation of energy.
- The ceiling fan is powered by electrical energy from an outlet.
- The energy from the outlet is used to drive the blades of the fan and set them into motion.
- This is mechanical energy.
Mass have no effect for the projectile motion and u want to know the height "h"
first,
find the vertical and horizontal components of velocity
vertical component of velocity = 12 sin 61
horizontal component of velocity = 12 cos 61
now for the vertical motion ;
S = ut + (1/2) at^2
where
s = h
u = initial vertical component of velocity
t = 0.473 s
a = gravitational deceleration (-g) = -9.8 m/s^2
h=[12×sin 610×0.473]+[−9.8×(0.473)2]
u can simplify this and u will get the answer
h=.5Gt2
H=1.09m
Speed = distance/time
Speed = 50/5
Speed = 10m/s
Answer: The volume of an irregularly shaped object is 0.50 ml
Explanation:
To calculate the volume, we use the equation:

Density of object = 
mass of object = 3.0 g
Volume of object = ?
Putting in the values we get:


Thus the volume of an irregularly shaped object is 0.50 ml
Answer with Explanation:
a. Option d is true.
a negatively charged plane parallel to the end faces of the cylinder
b. Radius of cylinder, r=0.66m
Magnitude of electric field, E=300 N/C
We have to find the net flux through the closed surface.
Net electric flux,


c.
Net charge,
Where




Where 