Answer:
0.3257 seconds
39.67 m/s
Explanation:
Speed = 263 km/h
Converting to m/s


Distance to travel = 23.8 m
Time = Distance / Speed

The time taken to go from one end of the court to the other is 0.3257 seconds
Time = 0.6 s
Speed = Distance / Time

The speed of the tennis ball is 39.67 m/s
Answer :
(a). The speed of the block is 0.395 m/s.
(b). No
Explanation :
Given that,
Diameter = 20.0 cm
Power = 26.0 MW
Mass = 110 kg
diameter = 20.0 cm
Distance = 100 m
We need to calculate the pressure due to laser
Using formula of pressure

![P_{r}=\dfrac{P}{Ac}Put the value into the formula[tex]P_{r}=\dfrac{26.0\times10^{6}}{\pi\times(10\times10^{-2})^2\times3\times10^{8}}](https://tex.z-dn.net/?f=P_%7Br%7D%3D%5Cdfrac%7BP%7D%7BAc%7D%3C%2Fp%3E%3Cp%3EPut%20the%20value%20into%20the%20formula%3C%2Fp%3E%3Cp%3E%5Btex%5DP_%7Br%7D%3D%5Cdfrac%7B26.0%5Ctimes10%5E%7B6%7D%7D%7B%5Cpi%5Ctimes%2810%5Ctimes10%5E%7B-2%7D%29%5E2%5Ctimes3%5Ctimes10%5E%7B8%7D%7D)

We need to calculate the force
Using formula of force


Put the value into the formula


We need to calculate the acceleration
Using formula of force

Put the value into the formula




(a). We need to calculate speed of the block
Using equation of motion

Put the value into the formula


(b). No because the velocity is very less.
Hence, (a). The speed of the block is 0.395 m/s.
(b). No
Answer:
The combination, L = I / (m * R) , that appears in the equation for the period of a physical pendulum, is called radius of oscillations
Hope this helps :]
To solve this problem we will use the basic concept given by the Volume of a sphere with which the atom approaches. The fraction in percentage terms would be given by the division of the total volume of the nucleus by that of the volume of the atom, that is,






Therefore the percent of the atom's volume is occupied by mass is 
Explanation:
Since, it is mentioned the there occurs no change in the temperature. This also means that there will occur no change in thermal energy of the system.
Hence,
= 0. And, as
= 0 then there will be no work involved. This means that total energy added to the house will return to the outside air as heat.
Therefore,
Q = -(19000 J + 2000 J)
= -21000 J
or, |Q| = 21000 J
Thus, we can conclude that the magnitude of the energy transfer between the house and the outside air is 21000 J.