Answer:
f = 692 N
Explanation:
given data:
f =800N
a =1.2 m s^{2}
m= 90 kg
from newton's second law
net force
therefore we have from above equation
ma =F - f
putting all value to get force of friction
1.2*90 = 800 - f
f = 692 N
Professor Martinez would like to describe the amount of variation there is in his data set. Which of the following should he cal
2 answers:
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T=2,5s
a=g≈10m/s²
h=s=?
"Non nobis, Domine, non nobis, sed Nomini tuo da gloriam."
Regards M.Y.
a=g≈10m/s²
h=s=?
"Non nobis, Domine, non nobis, sed Nomini tuo da gloriam."
Regards M.Y.