The amount of carbon combined with oxygen in order to form Carbon Dioxide(CO₂) is 12 grams
The Law of Multiple proportions is one of the basic laws in chemistry along with the Law of Definite proportion. This law was proposed by John Dalton in 1803. The law states that if two elements react to form one or more compounds then the ratio of masses of both the elements is in the ratio of small whole numbers.
It is known that Carbon can form two different compounds while reacting with Oxygen that is: Carbon Monoxide, Carbon Dioxide. For Carbon Monoxide, 12g of Carbon needs to react with 16g of Oxygen. Whereas, In Carbon Dioxide, 12g of Carbon needs to react with 32g of Oxygen. So the mass of Carbon is equal in both cases is 12g.
C(12g) + O(16g) ⇒ CO (Carbon Monoxide)
C(12g) + 2O(32g) ⇒ CO₂ (Carbon Dioxide)
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Answer:
The electric force is conservative.
Since
ΔK = −ΔU,
Kf − Ki =Ui −Uf.
We have,
Kf = 0
Ui = 0.
Thus Ki =Uf.
<u>so ,at 10 fm Uf = (2×10)−12 J.</u>
Answer : The final temperature is, 
Explanation :
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of water at 
= 150 g
= mass of water at 
= 100 g
= final temperature = ?
= temperature of lead = 
= temperature of water = 
= same (for water)
Now put all the given values in equation (1), we get
![150\times (T_{final}-363)=-[100\times (T_{final}-303)]](https://tex.z-dn.net/?f=150%5Ctimes%20%28T_%7Bfinal%7D-363%29%3D-%5B100%5Ctimes%20%28T_%7Bfinal%7D-303%29%5D)
Therefore, the final temperature is,
the pressure would be 292, did i calculate that right?
