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Alex_Xolod [135]
3 years ago
15

The magnitudes of the electric potential and of the electrostatic force depend on which factors?

Physics
2 answers:
artcher [175]3 years ago
6 0
<span>Distance and amount of charge.
Hope I helped :)</span>
mariarad [96]3 years ago
6 0
Size, type, and distance.
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Help with this I can’t come up with anything
kakasveta [241]
Let’s say you have a spring. You press on the spring with your finger. The spring goes down. This is the action force. Then, the spring goes back up after you take your finger off of it. This is known as the reaction force.
3 0
3 years ago
If the force of gravity changes, what happens to the weight of an object?
Nataly [62]
The "weight" is the name we give to the force of gravity on the object. They're the same thing.
7 0
3 years ago
How does gravity keep the moon in orbit around earth
lidiya [134]

Answer:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Explanation:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Answer is above

<em><u>Hope this helps.</u></em>

3 0
3 years ago
A pendulum has a mass of 1.5 kg and starts at a height of 0.4 m. If it is released from rest, how fast is it going when it reach
ella [17]

Answer:

A. 2.8 m/s

Explanation:

Suppose that at the height of 0 m, the path of the pendulum is lowest.

If we use law of conservation of energy, the pendulum will have zero kinetic energy or K.E when it is at highest point, because K.E happens during movement of object and at the highest point all the energy will be P.E

                                                    P.E= mgh

Similarly, when the pendulum reaches at the lowest point, the height becomes zero and the P.E also becomes zero. Now all the energy will be K.E

                                               K.E= 1/2 m v^2

In question, we are asked about the speed as the pendulum  it reaches the lowest point of its path. Like we mentioned P.E will be zero at lowest point  because of zero height. And also we will use law of conservation of energy because no energy has been lost from system.

                                                  K.E=     P.E

                                       1/2 m v^2  =   mgh

Taking sq.root at both sides

                                                  v= Under root 2 gh

                                                   v=Under root 2x 9.8 m/s x0.4 m

                                                   v=Under root 7.84

                                                    v=2.8 m/sec

Hope it helps!

3 0
3 years ago
As seen, any object with electric charge, stationary or moving, other than the charged object that created the field, experience
sammy [17]

Answer:

The answer and explanation is in the attached file

6 0
3 years ago
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