12 seconds after starting from rest a frewly falling cantaloupe has a speed of
1 answer:
Answer:
<em>The cantaloupe has a speed of 117.6 m/s</em>
Explanation:
<u>Free Fall Motion</u>
It occurs when an object falls under the sole influence of gravity. Any object that is being acted upon solely by the force of gravity is said to be in a state of free fall. Free-falling objects do not face air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is .
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The cantaloupe has been dropped from rest. We are required to find the speed after t=12 seconds.
Calculate the final speed:
vf=9.8 * 12 = 117.6 m/s
The cantaloupe has a speed of 117.6 m/s
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QUESTION:
Part A
The induced emf in the loop is measured to be . What is the magnitude
of the magnetic field that the loop was in?
Part B
For the case of a square loop of side length being pulled out of the magnetic field with constant speed
(see the figure), what is the rate of change of area
?
Answer:
Part A:
Part B:
Explanation:
Part A:
Faraday's law says that the induced voltage is equal to
,
which in our case(because we have only one loop) becomes
,
and since the magnetic field is uniform (not changing),
Now, we know that
therefore,
which gives us
Part B:
The area of the loop can be written as
,
where is the instantaneous length of the side along which the loop is moving.
Taking the derivative of both sides we get:
,
and since we have
where the negative sign indicates that the area is decreasing.