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alukav5142 [94]
3 years ago
6

if there are infinite universes is it possible that there is a universe where 1+1=3 or 4 or something

Physics
1 answer:
zhenek [66]3 years ago
8 0

Answer:

noooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo i said nooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

Explanation:

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An 800 N man climbs 5 m up a ladder. How much gravitational potential energy does he gain?
Artemon [7]

Answer:

4000J

Explanation:

Given parameters:

Weight of the man  = 800N

Height of ladder  = 5m

Unknown:

Gravitational potential energy gained  = ?

Solution:

The gravitational potential energy is due to the position of a body.

 Gravitational potential energy = weight x height

Now insert the parameters;

 Gravitational potential energy  = 800 x 5  = 4000J

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Two point charges are on the y axis. A 4.50-σC charge is located at y=1.25 cm , and a -2.24-σC charge is located at y=-1.80 cm.
kvasek [131]

Two point charges are on the y axis. A  4.50-σC charge (q_1) is located at y=1.25 cm (r_1) , and a -2.24-σC charge (q_2) is located at y=-1.80 cm (r_2).

The total electric potential at the origin is 2.12\times10^6V.

How to calculate the total electric potential at the origin?

The total electric potential at some point due to several point charges is represented by:

V=k_e  \sum _i \frac{q_i}{r_i}

Here,

k _e= 8.988 \times 10^9 N \cdot m^2/C^2 (Columbic constant)

The total electric potential at point O is the sum of the potentials due to q_1 and q_2 will be:

V_O=k_e(\frac{q_1}{r_1} +\frac{q_2}{r_2} )

Substituting the values, we get:

V_O=8.988\times10^9(\frac{4.5 \times 10^{-6}}{0.0125} +\frac{-2.24\times10^{-6}}{0.018} )=2.12\times10^6V

Hence, the total electric potential at the origin is2.12\times10^6V.4

To learn more about total electric potential, refer to:

brainly.com/question/16843018

#SPJ4

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2 years ago
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