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3 years ago

Which water would you use to make salt dissolve the slowest?

Physics

1 answer:

harkovskaia [24]3 years ago

4 0

Answer:

boiling water because salt dissolves quicker in hot Water and the hottest is boiling

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An object is placed 100 cm in front of a diverging lens of focal length -25cm. A converging lens of focal length 33 1/3 cm is pl

bagirrra123 [75]

We use 1/o + 1/i = 1/f where o is the distance of the object, i as distance of the image and f is the focal length.
Substituting, 1/ 100 + 1 / i = - 1 /25 
i = - 20 cm 

For the case of the problem,

o = (20 + 30) = 50 cm 

f = 33.33. Using 1 / i + 1 / o = 1/f , i = 100 cm 

M = magnification = - i / o 

m1 = -(-20)/100 = 20/100 = 0.2 

m2 = -100/50 = -2 

M = m1*m2 = -2 x 0.2 = -0.4.

8 0

3 years ago

3 things that Gravity affects

slamgirl [31]

Answer: See explanation

Explanation:

Gravity is simply referred to as the force of attraction between two particles or masses. Through gravity, the moon moves round the Earth.

Gravity also causes a fruit to fall from its tree. It can also cause an object to roll and fall from the table to the ground. In gravity, distance and mass are vital.

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3 years ago

What accomplishment from the space industry benefits society?

USPshnik [31]

The accomplishment from the space industry benefits society is for: b. the successful launch of communication satellites.
which is we as a society would get easier in our social communication.

hope this help

7 0

3 years ago

Read 2 more answers

What types of bond forms when two or more atoms share electrons?

atroni [7]

D) Hydrogen is the correct/ right answer because it says in the science book in the chapter that it is on to find the correct answer as well as look in the chapter that is on and look on the pages

8 0

3 years ago

Read 2 more answers

A point charge q1 = 4.10 nC is placed at the origin, and a second point charge q2 = -2.90 nC is placed on the x-axis at x = + 20

kaheart [24]

Answer:

1) U = -4.436 10-7 J , 2) r13 = 0.6937 m

Explanation:

The electric potential energy is given by the equation

U = k Σ $q_{i}$ $q_{j}$ / $r_{ij}$

1. Let's apply this equation to our case

U = k (q1q3 / r13 + q1 q2 / r12 + q2 q3 / r23)

Let's reduce all magnitudes to the SI system

q1 = 4.10 nC = 4.10 10-9 C

q2 = -2.90 nC = -2.90 10-09 C

q3 = 2.00 nC = 2.00 10-9 C

Let's look for the distances

r13 = 11-0 = 11 cm = 11 10-2 m

r12 = 20-0 = 20 cm = 20 10-2 m

r23 = 20 -11 = 9 cm = 9.0 10-2 m

Let's calculate the electric potential

U = 8.99 109 [(4.10 2.00) 10-18 / 11 10-2 + (4.10 (-2.90)) 10-18 / 20 10-2 + (-2.90 2.00) 10-18 / 9.0 10-2]

U = 8.99 [0.7455 - 0.5945 - 0.6444) 10-7

U = -4.436 10-7 J

2. ask to find the position of q3 for the energy to be zero

U = 0 = k (q1q3 / r13 + q1 q2 / r12 + q2 q3 / r23)

In this case the distance between 1 and 2 is fixed, since the load that is placed is 3

q1 q2 / r12 = - q1 q3 / r13 - q2 q3 / r23

-11.89 10-18 / 20 10-2 = -8.20 10-18 / r13 + 5.810-18 / r23

-0.5945 102 = -8.20 / r13 + 5.810 / r23

Let's relate the distances, the maximum separation esr12 which is 20 10-2 m

r12 = r13 + r23

r13 = r12 -r23

r13 = 2010-2 - r23

we replace

-0.5945 102 = -8.20 / (20 10-2 - r23) + 5.810 / r23

Let's solve this equation

-0.5945 102 (2010-2 - r23) = -8.20 r23 + 5.810 (2010-2 - r23)

- 11.89 + 0.5945 r23 = -8.20 r23 + 1,162 - 5,810 r23

-11.89 - 1,162 = - 8.20 r23 -5,810 r23 - 0.5945 r23

-13.052 = r23 (-14.6045)

r23 = 13.052 / 14.6045

r23 = 0.8937 m

The distance from the origin is

r13 = -r12 + r23

r13 = -20 10-2 + 0.8937

r13 = 0.6937 m

3 0

3 years ago