1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kondaur [170]
3 years ago
6

Are volcanoes fed by highly viscous magma a greater threat to life and property than volcanoes supplied with very fluid magma?

Physics
1 answer:
butalik [34]3 years ago
3 0

Answer:

A volcano fed by highly viscous magma is likely to be a greater threat to life and property than a volcano supplied with very fluid magma because with high viscous magma gas is trapped more in the magma so the gas will build up and then eventually explode, whereas with fluid magma the gas can escape allowing the magma.

HOPE THIS HELPS!!!

Explanation:

You might be interested in
( pls help me i worked hard for these points! i hope u will not write anything for the points pls help me! due is today)
Damm [24]

Answer:

a) 500 m

b) 50 s

c) speed= distance/time= 500/50= 10 m/s

hope it helps! please mark me brainliest

thank you! have a good day ahead

if u follow me, I will follow u back!

7 0
3 years ago
A cake is removed from a 350◦F oven and placed on a cooling rack in a 70◦F room. After 30 minutes the cake is 200◦F. When will i
galben [10]

Answer:

350 F to 100 F it take approx 87.33 min  

Explanation:

given data

oven = 350◦F

cooling rack = 70◦F

time = 30 min

cake = 200◦F

solution

we apply here Newtons law of cooling  

\frac{dT}{dt} = -k(T-Ta)

\frac{dy}{dt} = \frac{d}{dt} (T(t) -Ta)

= \frac{dT}{dt} -\frac{dTa}{dt} =\frac{dT}{dt} = -k(T-Ta)

-ky \frac{dy}{dt} = -ky

T(t) -Ta = (To -Ta) e^{-kt} T(t) = Ta+ (To -Ta)  e^{-kt}

put her value for time 30 min and T(t) = 200◦F and To =350◦F  and Ta = 70◦F

so here

200 = 70 + ( 350 - 70 ) e^{-k30}

k = 0.025575

so here for  T(t) = 100F

100 = 70 + ( 350 - 70 ) e^{-0.025575*t}

time = 87.33 min

so here 350 F to 100 F it take approx 87.33 min  

5 0
4 years ago
What does a moving charge experience when it is near a magnetic field
mars1129 [50]
When a moving charge is near a magnetic field, it experiences a force. The magnetic field has the ability to attract or repel charge in a magnetic field, and thus the moving charge will experience a force on it. Hope this helps.
3 0
3 years ago
A proton (mass=1.67x10^-27 kg, charge= 1.60x10^-19 C) moves from point A to point under the influence of an electrostatic force
Tom [10]

Answer:

VB -  VA  =  - 33.4

Explanation:

Generally the workdone in moving the proton is mathematically represented as

     W  =  KE_f  - KE_i

Where KE_i \ and \  KE_f \  are\  the\  initial  \  and  \  final \  kinetic \  energy

So

    KE_i  =  \frac{1}{2} m v_a^2

Here v_a is the velocity at A with value  50 m/s

So

    KE_i  =  \frac{1}{2} (1.67*10^{-27}) * 50^2

    KE_i  = 2.09 *10^{-24} \  J

Also  

     KE_f  =  \frac{1}{2} m v_b^2

Here v_a is the velocity at A with value 80 km/s = 80000 m/s

=>   KE_f  =  \frac{1}{2} (1.67*10^{-27}) * 80000^2

=>   KE_f  = 5.34 *10^{-18} \  J

 So

    W  =   5.34 *10^{-18}  - 2.09 *10^{-24}

     W  =   5.34 *10^{-18}  m/s

Now this workdone is also mathematically represented as

     W =  q *  V

So  

    q *  V =   5.34 *10^{-18}

Here  q =  1.60*10^{-19} C

So

        V =   \frac{5.34 *10^{-18} }{1.60*10^{-19}}

         V =   33.4 \  V

Generally proton movement is in the direction of the electric field it means that  VA>VB

So

    VB -  VA  =  - 33.4

8 0
3 years ago
The densities of cardboard, aluminum, and lead are 0.6 g/cm^3, 2.7 g/cm^3, and 11.4 g/cm^3, respectively. Suppose that you are s
krek1111 [17]

Answer:

For cardboard = 29.4 g/cm²

For aluminium = 113.4 g/cm²

For lead = 193.8 g/cm²

Explanation:

Given:  

Density of the cardboard, d₁ = 0.6 g/cm³

Density of the aluminium, d₂ = 2.7 g/cm³

Density of the lead, d₃ = 11.4 g/cm³

Length of the cardboard,  L₁ = 49 cm

Length of the aluminium, L₂ = 42 cm

Length of the lead, L₃ = 17 cm

Now,

The absorber thickness is calculated as:

= Density × Length

therefore,

For cardboard = d₁ × L₁ = 0.6 × 49 = 29.4 g/cm²

For aluminium = d₂ × L₂ = 2.7 × 42 = 113.4 g/cm²

For lead = d₃ × L₃ = 11.4 × 17 = 193.8 g/cm²

4 0
4 years ago
Other questions:
  • An astronaut out on a spacewalk to construct a new section of the International Space Station walks with a constant velocity of
    14·1 answer
  • A girl weighing 500 Newton’s climbs 40 m vertically when walking up the stairs.what How much work does she do against gravity
    12·1 answer
  • All indicate that the universe is
    15·2 answers
  • Explain how it is possible for the smallest white dwarfs to be the most massive.
    11·1 answer
  • A boy having 0.2kg toy tied with a sting, having force 2N, angle 60º displaces it 5 m. What is the work done?
    10·1 answer
  • 2. A car with mass 2,500 kg is travelling at 15 m/s. What is the car's kinetic energy?
    12·1 answer
  • Can someone complete this assignment will give brainliest!<br> The assignment is attached
    13·1 answer
  • How light is bends by gravity?​
    10·1 answer
  • Which direction do electrons travel
    13·1 answer
  • A 5 kg box is sitting on a rough wooden surface. The coefficient of static friction between the box and surface is 0.6. If the n
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!