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miss Akunina [59]
3 years ago
14

how many H+ ions are in a solution with a pH of 2 and how many H+ ions are in a solution with a pH of 6?

Chemistry
1 answer:
LiRa [457]3 years ago
3 0

Answer:

i) pH = 2

pH = -log(H+)

:- (H+) = 10^(-2)

:- (H+) = 0.01 M

ii) pH = 6

pH = -log(H+)

:- (H+) = 10^(-6)

:- (H+) = 0.000001 M

Explanation:

By definition: pH = -log(H+).

Given your pH, solve for the H+ using the the following log rule:

if a = (+/-) log (b) then

b = 10^((+/-) a).

Also remember unit of concentration is molar (M)

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7 0
3 years ago
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A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the io- dide i
Sergeeva-Olga [200]

Answer:

m_{I^-}=1.18gI^-

Explanation:

Hello,

In this case, the reaction is given as:

I^-+AgNO_3\rightarrow AgI+NO_3^-

Thus, starting by the yielded grams of silver iodide, we obtain:

n_{I^-}=2.185gAgI*\frac{1molAgI}{234.77gAgI}*\frac{1molI}{1molAgI}=9.31x10^{-3}molI^-

Which correspond to the iodide grams in the silver iodide. In such a way, by means of the law of the conservation of mass, it is known that the grams of each atom MUST remain constant before and after the chemical reaction whereas the moles do not, therefore, the mass of iodine from the silver iodide will equal the mass of iodine present in the soluble iodide, thereby:

m_{I^-}=9.31x10^{-3}molI^-\frac{127gI^-}{1molI^-} =1.18gI^-

And the rest, correspond to the iodide's metallic cation which is unknown. Such value has sense since it is lower than the initial mass of the soluble iodide which is 1.454g, so 0.272 grams correspond to the unknown cation.

Best regards.

7 0
4 years ago
Based on the simulation activity and understanding how magnets have their own magnetic field explain what might make the magneti
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4 0
2 years ago
There is 35 mg of sodium in a can of Coke. You determine it to be 28 mg. What is your percent error?
natali 33 [55]

Answer:

The answer is

<h2>20 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual volume = 35 mg

error = 35 - 28 = 7

The percentage error is

P(\%) =  \frac{7}{35}  \times 100 \\  =  \frac{1}{5}  \times 100 \\  =  20

We have the final answer as

<h3>20 %</h3>

Hope this helps you

8 0
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