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mihalych1998 [28]

3 years ago

13

How much energy must be added to 2 mol H2O(g) to cause it to decompose into H2 and O2?

2 answers:

nika2105 [10]3 years ago

3 0

The forward reaction is:
2H₂(g) + O₂(g) → 2H₂O(g); ΔH = -484 kJ

The forward reaction releases 484 kilojoules of energy to form water. As per the reaction equation, in order to cause two moles of water to decompose and make the reaction proceed backwards, 484 kilojoules of energy must be added to water.

balandron [24]3 years ago

3 0

Answer: How much energy must be added to 2 mol H2O(g) to cause it to decompose into H2 and O2?

483.64 kJ

Explanation:

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What are some examples of supersaturated solutions? Give 10.

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The melting point and freezing point of silver are 960 degrees celsius and 2162 degrees celsius, repectively. What is the freezi

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What is the molar mass of MnP

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3 years ago

A compound is found to contain 64.80 % carbon, 13.62 % hydrogen, and 21.58 % oxygen by weight. What is the empirical formula for

insens350 [35]

Answer:

Empirical formula is C₄H₁₀O

Explanation:

Values for C, H and O are determined as centesimal composition.

64.80 g of C in 100g of compound

13.62g of H in 100 g of compound

21.58 g of O in 100 g of compound.

We convert the mass to moles:

64.80 g . 1mol/ 12g = 5.4 moles of C

13.62 g . 1 mol /1g = 13.62 moles of H

21.58 g . 1 mol/16g = 1.35 moles of O

We pick the lowest value and we divide:

5.4 moles of C / 1.35 = 4 C

13.62 moles of H / 1.35 = 10 H

1.35 moles of O / 1.35 = 1 O

Empirical formula is C₄H₁₀O, it can be the diethyl ether.

We confirm, the excersise is well done.

Molar mass = 74g/mol

74 g of compound we have (12 . 4)g of C

In 100 g of compound we may have (100 . 48) / 74 = 64.8 g

5 0

3 years ago

He balanced equation for the reaction of acetylene, c2h2, and oxygen in an acetylene torch is 2 c2h2 + 5 o2 → 4 co2 + 2 h2o. in

pickupchik [31]

Answer: 0.4 g

Explanation:

1) Balanced chemical equation:

2) 2C2H2 + 5 O2 → 4CO2 + 2 H2O

3) mole ratios:

2 mol C2h2 : 5 mol O2

4) Convert 0.13 g C2H2 into number of moles

n = mass in grams / molar mass

molar mass C2H2 = 2 *12g/mol + 2*1 g/mol = 26 g/mol

n = 0.13 g / 26 g/mol = 0.005 mol

5) Set the proportion with the unknown

5 mol O2 x
----------------- = ---------------
2 mol C2H2 0.005 mol C2H2

x = 0.005 mol C2H2 * 5 mol O2 / 2 mol C2H2 = 0.0125 mol O2

6) Convert 0.0125 mol O2 to grams

mass = number of moles * molar mass

molar mass of O2 = 32 g/mol

mass = 0.0125 mol * 32 g/mol = 0.4 g

Answer: 0.4 g

8 0

3 years ago