Answer:

Explanation:
In this case the kinetic energy of the bike is converted into the heat energy between the area of contact of tyre and the road. This happens due to the work done by the frictional force between the surface to stop the relative motion between the road and the tyre.
Given:
- normal force on the rear tyre,

(as given in the question that the rear tyre supports half the combined weight of the bike and the rider.)
- distance dragged while stopping the tyre,

- coefficient of kinetic friction between the surfaces,

<u>Now, frictional force between the surfaces:</u>



<u>Now, the work done by the kinetic friction:</u>



According to the energy conservation this amount of energy is converted into thermal energy between the surfaces in contact, i.e. road and the tyre.
Answer:
Pretty sure it is air mass C
Explanation:
It looks like yhe air has warm air where as the other 2 options have cold air.
Explanation:
velocity of disc 
lets call (h) 1 m to make it simple.
= 3.614 m/s
m/s pointing towards this:


velocity of hoop=
lets call (h) 1m to make it simple again.
m/s
![\sqrt(gh) = sqrt(hg)so [tex]4×V_d= \sqrt(4/3hg)V_h=\sqrt(hg)](https://tex.z-dn.net/?f=%5Csqrt%28gh%29%20%3D%20sqrt%28hg%29%3C%2Fp%3E%3Cp%3Eso%20%5Btex%5D4%C3%97V_d%3D%20%5Csqrt%284%2F3hg%29V_h%3D%5Csqrt%28hg%29)
The disc is the fastest.
While i'm on this subject i'll show you this:
Solid ball 
solid disc 
hoop 
The above is simplified from linear KE + rotational KE, the radius or mass makes no difference to the above formula.
The solid ball will be the faster of the 3, like above i'll show you.
solid ball: velocity 
let (h) be 1m again to compare.
m/s
solid disk speed 
uniform hoop speed 
solid sphere speed 