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3 years ago

(i) A stone is thrown vertically upwards with an initial velocity of 60ms. Find

Physics

2 answers:

Alex777 [14]3 years ago

7 0

Answer:

i) 180m ii) 6sec ii)180m

Explanation:

i) Hmax = U²/2g

= 60²/20

= 3600/20= 180m

ii). Tmax= U/g

= 60/10= 6sec

iii). X= ut²+ 1/2gt²

since U is 0,then ut=0

X=0+ 1/2×10×6²

X=5×36= 180m

hope its clear??

elixir [45]3 years ago

5 0

Answer:

plzzzzzzz follow me back

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A grinding wheel is a uniform cylinder with a radius of 8.65 cm and a mass of 0.400 kg . Calculate its moment of inertia about i

anyanavicka [17]

Answer:

I = 1.5*10⁻³ kg*m²

Explanation:

It can be showed that the moment of inertia (or rotational inertia) for a uniform cylinder of mass m and radius r, respect an longitudinal axis going through its center (parallel to the height of the cylinder) can be written as follows:

$I = \frac{1}{2}*m*r^{2} = \frac{1}{2}*0.400 kg*(0.0865m)^{2} = 1.5e-3 kg*m2$

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3 years ago

A Heavy crate applied a force of 1500 N on a 25m2 piston. What force needs to be applied on a 0.8m2 piston to lift the crate?

Aleks04 [339]

25/1500 is equal to 0.8/x
0.8*1500 is equal to 1200
1200/25 is equal to 48 N

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3 years ago

Read 2 more answers

Una patinadora de 50 kg parte del reposo y después de recorrer 3k alcanza una velocidad de 15 m/s. ¿Qué fuerza neta experimenta

e-lub [12.9K]

Answer:

$F_{net} = 1.875\,N$

Explanation:

Asúmase que la patinadora experimenta una aceleración constante. La fuerza neta experimentada por la patinadora:

$F_{net} = (50\,kg)\cdot \left[\frac{\left(15\,\frac{m}{s}\right)^{2}-\left(0\,\frac{m}{s}\right)^{2} }{2\cdot (3000\,m)} \right]$

$F_{net} = 1.875\,N$

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3 years ago

A woman walked 115 m. As she did so, her speed increased from 4.20 m/s to 5.00 m/s. How long did it take her to walk this distan

ASHA 777 [7]

Answer:

25 seconds

Explanation:

Assuming the woman is accelerating at a constant rate of $a \;\;m/s^2$ from the initial velocity, u=4.20 m/s, to the final velocity, v=5.00 m/s.

Let she takes t seconds to cover the distance, s=115 m.

As acceleration, $a=\frac{v-u}{t}=\frac{5-4.2}{t}$

$\Rightarrow at=0.8\cdots(i)$

Now, from the equation of motion

$s=ut+\frac 12 at^2$

$\Rightarrow s=ut+\frac 12 at(t)$

$\Rightarrow 115=4.2t+\frac 12 \times 0.8 t$ [ from equation (i)]

$\Rightarrow 115=(4.2+0.4)t$

$\Rightarrow t= 115/4.6 = 25$ seconds.

Hence, she takes 25 seconds to walk the distance.

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3 years ago

A girl attempts to swim directly across a stream 15meters wide. When she reaches the other side, she is15 meters downstream. The

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X
=
√
15
2
+
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2

x
=
15
√
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3 years ago