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Sveta_85 [38]
3 years ago
5

What force acts on a projectile in the horizontal direction?

Physics
2 answers:
Anna35 [415]3 years ago
5 0

Answer:

the answer is gravity

Explanation:

natita [175]3 years ago
3 0

Answer: horizontal force

Explanation:

i think

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allochka39001 [22]

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An engineer weighs a sample of mercury (ρ = 13.6 × 103 kg/m3 ) and finds that the weight of the sample is 6.0 n. what is the sam
Amanda [17]
Given:
ρ = 13.6 x 10³ kg/m³, density of mercury
W = 6.0 N, weight of the mercury sample
g = 9.81 m/s², acceleration due to gravity.

Let V =  the volume of the sample.
Then
W = ρVg
or
V =  W/(ρg)
   = (6.0 N)/[(13.6 x 10³ kg/m³)*(9.81 m/s²)]
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3 years ago
Beta particles cannot penetrate very far into solids because they _____. a. have low velocity b. have negligible mass c. have no
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Beta particle cannot penetrate theory for into the solid because they have lower velocity
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To get a feeling for inertial forces discuss the familiar cases of accelerating in a car in a straight line while increasing or
inn [45]

Answer:

Explanation:

When we accelerate in a car on a straight path we tend to lean backward because our lower body part which is directly in contact with the seat of the car gets accelerated along with it but the upper the upper body experiences this force  later on due to its own inertia. This force is accordance with Newton's second law of motion and is proportional to the rate of change of momentum of the upper body part.

Conversely we lean forward while the speed decreases and the same phenomenon happens in the opposite direction.

While changing direction in car the upper body remains in its position due to inertia but the lower body being firmly in contact with the car gets along in the direction of the car, seems that it makes the upper body lean in the opposite direction of the turn.

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7 0
3 years ago
Given: G = 6.672 × 10−11 N · m2 /kg2 Io, a satellite of Jupiter, has an orbital period of 1.24 days and an orbital radius of 4.1
Dahasolnce [82]

Answer:

Mass of Jupiter = 4.173×10^15kg

Explanation:

Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:

T^2 = GM/4 pi × r^3

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r = radius

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Rearranging the formular to make M the subject of formular

T^2 × 4 pi = G M × r^3

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6 0
3 years ago
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