Answer:
6the first is a one block and the two are u to be the best in freefire with the best and best name to get
Explanation:
the first time he was a boy and a girl in the 6AM he is a girl who has 6666th grade 6inches
Given:
ρ = 13.6 x 10³ kg/m³, density of mercury
W = 6.0 N, weight of the mercury sample
g = 9.81 m/s², acceleration due to gravity.
Let V = the volume of the sample.
Then
W = ρVg
or
V = W/(ρg)
= (6.0 N)/[(13.6 x 10³ kg/m³)*(9.81 m/s²)]
= 4.4972 x 10⁻⁵ m³
Answer: The volume is 44.972 x 10⁻⁶ m³
Beta particle cannot penetrate theory for into the solid because they have lower velocity
Answer:
Explanation:
When we accelerate in a car on a straight path we tend to lean backward because our lower body part which is directly in contact with the seat of the car gets accelerated along with it but the upper the upper body experiences this force later on due to its own inertia. This force is accordance with Newton's second law of motion and is proportional to the rate of change of momentum of the upper body part.
Conversely we lean forward while the speed decreases and the same phenomenon happens in the opposite direction.
While changing direction in car the upper body remains in its position due to inertia but the lower body being firmly in contact with the car gets along in the direction of the car, seems that it makes the upper body lean in the opposite direction of the turn.
On abrupt change in the state of motion the force experienced is also intense in accordance with the Newton's second law of motion.
Answer:
Mass of Jupiter = 4.173×10^15kg
Explanation:
Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:
T^2 = GM/4 pi × r^3
Where G = universal gravitational constant
r = radius
M = masd of jupiter
Rearranging the formular to make M the subject of formular
T^2 × 4 pi = G M × r^3
(T^2 × 4 pi) / (G× r^3) = M
(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3
M = 19.32 /6.672×10^-11)(4.11×10^8)^3
M = 19.32 / 4.63 ×10^15
M = 4.173×10^15kg