The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
(1,6) , (2,7) , (3,8) , (4,9) , (5,10)
Step-by-step explanation:
Given equation: y = x + 5
when x = 1, y = 1 + 5 = 6
(1,6)
when x = 2, y = 7
(2,7)
when x = 3 , y = 8
(3,8)
when x = 4 , y = 9
(4,9)
when x = 5 , y = 10
(5,10)
Correct answer:
26 = -13x
X = -2
if you need a false answer, make up any number!
Answer:
m=4
best of luck!
Step-by-step explanation:
Answer: solutions are the same, just written differently, inequality sign is reversed when multiplying by a negative. Yes, both students are correct.Jul 8, 2018
Step-by-step explanation: