The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
1. She got 9 questions wrong.
2. I believe the total is $44.80
Answer:
210
Step-by-step explanation:
JQ is 5 times the length of JK
● JQ = 5JK
JK = 42
● JQ = 5 × 42
● JQ = 210
The answer is 30
6+8•3
6+24 =30
Answer:
522 m^2
Step-by-step explanation:
I've circles the numbers that you actually need to solve this problem.
First, find the area of the bigger rectangle by multiplying the length and width.
24*21=504
Then find the area of the smaller rectangle the same way
3*6=18
then add them to get the total area
504+18=522
522 m^2