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3 years ago

The term

Physics

1 answer:

stellarik [79]3 years ago

5 0

Answer:

C. simple

The term that refers to the fact that an epithelial tissue has only one layer of cells is simple epithelial.

Explanation:

Epithelial tissues are thin tissues that cover all the exposed surfaces of our body.

Based on the number of cell layers, the simplest classification of epithelial tissue is:

a. Simple Epithelial Tissue

When the epithelial tissue consists of a single layer of cells, it is called simple epithelial tissue.

b. Stratified Epithelial Tissue

When there are two or more layers of cells in epithelial tissue, it is called stratified epithelial tissue.

Cuboidal epithelial is also a type of simple epithelial tissue.

Pseudostratified is another type of epithelial tissue which falls in neither simple nor stratified category. They consists of a single layer but the positioning suggests it is stratified.

There are 3 types of epithelial tissues based on their shape:

a. Squamos epithelial tissue

b. Cuboidal epithelial tissue

c. Columnar epithelial tissue

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Answer:

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Explanation:

Here Mass flux of water vapour is given as

$j_{H_2O}=\frac{D}{l} \bigtriangleup c$

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$j_{H_2O}$ is the mass flux of the water which is to be calculated.

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$\bigtriangleup c= \frac{P_{sat}-P_a}{RT}$

In this

$P_{sat}$ is the saturated water pressure, which is look up from the saturated water property at 20°C and 0.5 saturation given as 2.34 Pa

$P_a$ is the air pressure which is given as 0.5 times of $P_{sat}$

R is the universal gas constant as $8.314 kJ/kmol-K$

T is the temperature in Kelvin scale which is $20+273= 293K$

By substituting values in the equation

$\bigtriangleup c= \frac{P_{sat}-P_a}{RT} \\ \bigtriangleup c= \frac{P_{sat}-0.5P_{sat}}{RT} \\ \bigtriangleup c= \frac{0.5P_{sat}}{RT} \\ \bigtriangleup c= \frac{0.5 \times 2.34}{8.314 \times 293} \\\bigtriangleup c= 0.48 mol/m^3$

Converting $\bigtriangleup c$ into $cm^3/cm^3$

As 1 mole of water 18 $cm^3$ so

$\bigtriangleup c= 0.48 mol/m^3 \\ \bigtriangleup c= 0.48 \times 18 \times 10^{-6} cm^3/cm^3 \\ \bigtriangleup c= 8.64 \times 10^{-6} cm^3/cm^3$

Putting this in the equation of mass flux equation gives

$j_{H_2O}=\frac{D}{l} \bigtriangleup c \\ j_{H_2O}=\frac{0.25}{0.15} \times 8.64 \times 10^{-6} \\ j_{H_2O}=14.4 \times 10^{-6} cm/s$

For calculation of water level drop in a day, converting mass flux as

$j_{H_2O}=14.4 \times 10^{-6} \times 24 \times 3600 cm/day\\ j_{H_2O}=1.24 cm/day$

So the water level will drop by about 1.24 cm in 1 day.

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Correct answers:

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- Decreasing the cross-sectional area of the wire will increase the resistance of the wire.

- Increasing the length of the wire will increase the resistance of the wire.

Explanation:

The resistance of a wire is given by:

$R=\rho \frac{L}{A}$

where

$\rho$ is the resistitivity of the material

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From the formula, we can notice that:

- The resistance (R) is directly proportional to both the resistivity ( $\rho$ ) and the length of the wire (L), so when one of these quantities increases, the resistance will increase as well

- The resistance (R) is inversely proportional to the cross-sectional area (A), therefore when the resistance increases when the cross-sectional area decreases.

Based on these observations, the correct statements are:

- Increasing the resistivity of the material the wire is composed of will increase the resistance of the wire.

- Decreasing the cross-sectional area of the wire will increase the resistance of the wire.

- Increasing the length of the wire will increase the resistance of the wire.

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