Answer:
the correct affirmation is the 3
Explanation:
Let's analyze the problem with Newton's second law before looking at the claims.
X axis parallel to the plane, positive down
F -fr + Wₓ = ma
Y Axis perpendicular to the plane
N -Wy = 0
With trigonometry
Wₓ = W sin θ
Wy = w cos θ
Let's multiply by the displacement along the plane, to relate to the work, which has as expression W = F d
F d -fr d + Wx d = ma d
Push W₁ = Fd
frictional force W₂ = -fr d
gravity W₃ = Wx d
W₁ + W₃ -W₂ = m a d
Analysis affirmations:
R1) false. The work of gravity is the subtraction
R2) false. Each force contributes according to its magnitude
R3) true. In the equation we see that, if the acceleration is zero, W2 = W1 + W3
R4) False. It equals the difference
the correct affirmation is the 3
Hi, here is the first part of the answer..do you know what type of graph it's wanting?? (line graph, bar graph, ect.)
Work done=mgh
W=force*height
W=5N*0.50mts
W=2.5joule
Answer:
Kinetic Energy at bottom=2886.5J (when g=9.8m/s²)
<em><u>OR</u></em>
2925J (if g=10m/s²)
Answer:
9.9 m
Explanation:
From the question given above, the following data were obtained:
Force (F) = 40 N
Workdone (Wd) = 395 J
Height (h) =?
The height can be obtained as follow:
Potential energy = mgh = Fh
395 = 40 × h
Divide both side by 40
h = 395 / 40
h = 9.9 m
Thus, the height is 9.9 m.
