The coefficient of static friction is 0.234.
Answer:
Explanation:
Frictional force is equal to the product of coefficient of friction and normal force acting on any object.
So here the mass of the object is given as 2 kg, so the normal force will be acting under the influence of acceleration due to gravity.
Normal force = mass * acceleration due to gravity
Normal force = 2 * 9.8 = 19.6 N.
And the frictional force is given as 4.6 N, then

Coefficient of static friction = 4.6 N / 19.6 N = 0.234
So the coefficient of static friction is 0.234.
Answer:
26945.6 ft⋅lbf
Explanation:
Volume of Right Circular Cone = pi*(radius^2)*(height/3)
Pi*(4)*(5/3) = 20.94 ft^3
Density = Mass / Volume
Mass = Density*Volume
Mass = (40)*(20.94)
Mass = 837.6 lb
Work = Force*Height
Force = Mass*Acceleration
Acceleration will be gravitational acceleration
Work = (837.6)*(32.17)*(1)
Work = 26945.6 ft⋅lbf
The answer is c and my reason is I have straight As