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Vika [28.1K]
3 years ago
12

HELP WILL MARK YOU BRAINLIEST NO GUESSES PLZ!!!!

Mathematics
2 answers:
kumpel [21]3 years ago
8 0

Answer:

d - the lines intersect,but are not perpendicular

Step-by-step explanation:

omg I know for a fact this is correct I took this test ....

your welcome!

bazaltina [42]3 years ago
7 0

the answer is D and i know cause i just did that and thats the answer

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Find the zeros and complete the factorization
vovikov84 [41]

Answer:

(x^{2} -\sqrt{5} )(x^{2} +\sqrt{5} )(x^{2} +4)

Step-by-step explanation:

x^{4} -x^{2} -20\\if x^{2} =y\\y^{2} -y -20\\y^{2} -5y +4y - 20\\y(y-5)+4(y-5)\\(y-5)(y+4)\\since x^{2} =y\\(x^{2} -5)(x^{2} +4)\\(x^{2} -\sqrt{5} )(x^{2} +\sqrt{5} )(x^{2} +4)

6 0
3 years ago
Is there anyone in this world who will help me with my math? i really need help
lidiya [134]

Do you remembered me? Yes I’ll help too.

4 0
3 years ago
Which of the following functions have a vertical asymptote for values of Ø such that cos Ø = 1?Select all that apply.
igomit [66]

Answer:

y=\cot \theta and y=\csc \theta

Step-by-step explanation:

Note that if \cos \theta=1, then \sin \theta=0.

Functions y=\cos \theta,\ \ y=\sin \theta do not have vertical asymptotes at all.

Vertical asymptotes have functions y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.

Functions y=\tan \theta and y=\sec \theta have the same vertical asymptotes (when \cos \theta =0).

Functions y=\cot \theta and y=\csc \theta have the same vertical asymptotes (when \sin \theta =0). See attached diagram

3 0
4 years ago
Wat is 20/24 as a decimal and a percent
Morgarella [4.7K]
\frac{20}{24}=\frac{20:4}{24:4}=\frac{5}{6}\\\\\\\frac{5}{6}=0.8333...=0.8(3)\\\\\\\frac{5}{6}=\frac{5}{6}\cdot100\%=\frac{5}{3}\cdot50\%=\frac{250}{3}\%=83\frac{1}{3}\%
7 0
3 years ago
Read 2 more answers
which of the following equations can be used to calculate the values of t for which the distance between Chris and any is 300 mi
Papessa [141]
The first thing we must know in this case is that the distance is equal to the speed for time.
 We have then:
 For Chris:
 d1 = 40 * t
 For Amy:
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 The distance between both will be given by the hypotenuse of the rectangle triangle:
 300 = root ((40 * t) ^ 2 + (60 * (t-2)) ^ 2)
 Answer:
 300 = root ((40 * t) ^ 2 + (60 * (t-2)) ^ 2) 
 option 3
8 0
3 years ago
Read 2 more answers
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