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Lubov Fominskaja [6]
3 years ago
11

A package is in the shape of a triangular prism. The bases are right triangles with perpendicular legs measuring 9 centimeters a

nd 12 centimeters. The distance between the bases is 10 centimeters. What is the surface area of the triangular prism? square centimeters
Mathematics
2 answers:
uranmaximum [27]3 years ago
4 0

Answer: 468 square centimeters


Step-by-step explanation:

The surface area of each of the triangular base is A=\frac{1}{2}ab

where a and b are the perpendicular legs of triangle (the triangular base must be right triangle)

⇒The surface area of each of the triangular base A=\frac{1}{2}9\cdot12=54\ cm^2

The third side of triangular base =H=\sqrt{9^2+12^2}

\\\Rightarrow\ H=\sqrt{81+144}\\\Rightarrow\ H=\sqrt{225}\\\Rightarrow\ H=15\ cm

Then the lateral areas of each rectangle of dimensions 10 × 9, 10 × 12, and 10 × 15.

Thus the total lateral area is 10\times9+10\times12+10\times15=10(9+12+15)=10\times36=360\ cm^2

The total surface area is =2\times54+360=108+360=468cm^2



ryzh [129]3 years ago
3 0
45 I think  is the answer if 9 is the height and 10 is the base then 45 is the answer <span />
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