The given question is incomplete, the complete question is:
Calculate the free energy of formation of NaBr(s) given the following information: NaBr(s) → Na(s) + 1/2Br2(l), ΔG° = 349 kJ/mol
A) –309 kJ/mol
B) –329 kJ/mol
C) None of the above
D) –349 kJ/mol
E) –369 kJ/mol
Answer:
The correct answer is option D, that is, -349 kJ/mol.
Explanation:
Based on the given information, the reaction is:
NaBr (s) ⇔ Na (s) + 1/2 Br₂ (l), the ΔG° of the reaction given is 349 kJ per mole. In the given question, it is clearly mentioned that there is a need to determine the free energy of the formation of NaBr. Thus, there is a need to keep Na (s) and Br₂ (l) at the reactant side and NaBr (s) at the product side.
Therefore, there is a need to reverse the reaction and change the sign on ΔG.
Now the reaction will become,
Na (s) + 1/2 Br₂ (l) ⇔ NaBr (s), and the ΔG° will now become -349 kJ per mole. Hence, -349 kJ per mole is the free energy of the formation of NaBr (s).
Ead sulfide + oxygen lead oxide + sulfur dioxide
2 PbS(s) + 3 O2(g) 2 PbO(s) + 2 SO2<span>(g)
Hope this is what you are asking for :))</span>
The gross colors can be imparted to the flame by the metal ion solutions .
1.To serve as an excitation source, turn on a Bunsen burner.
2. Perform flame tests on the chloride solutions of Li+, Na+, K+, Ca2+, Sr2+, and Ba2+ as instructed by your lab instructor. Wearing the unique glass blower glasses, take note of the obscene hue that each ion contributes to the flame. With one exception: in order to view the sodium flame, you must remove the special glasses that suppress sodium emissions.
3. Obtain two unidentified answers and note their numerical values. Using the ugly hue the solution gives the flame as a guide, identify the metal ions that are present.
One of the six ions you tested will make up the particle.
To know more about continuous spectrum, please refer:
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Answer:
Explanation:
The equation of the reaction is given as:
Given that:
[ATP] = 5.00 mM
[ADP] = 0.40 mM
[HPO₄²⁻] = 5.00 mM
converting mM to M; we have:
5.00 mM = 5.00 mM × 1 M/ 1000 mM
= 0.005 M
0.40 mM = 0.40 mM × 1 M/ 1000 mM
= 0.0004 M
The equilibrium constant is:
= 0.0004
Given that:
To Joule (J) ; we have
Temperature T = 37° C = (37+ 273)K = 310 K
is then calculated by using the equation:
Since is negative; the hydrolysis of ATP is spontaneous .