1s2,2s2.2p6,3s2,3p6,3d4,4s2
The answers would be the mass before a reaction is the same as the mass after a reaction which basically means mass is conserved
Combustion equation of n-hexane:
2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O
a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles
LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1%
b)
1.1 volume percent required for LFL
1.1% x 1
= 0.0011 m³ of n-hexane required
Answer:
75 g
Explanation:
1 half life = 600/2 = 300g
2 half life = 300/2 = 150g
3 half life = 150/2 = 75g
