Complete this equation for the dissociation of K3PO4(aq). Omit water from the equation because it is understood to be present.

Chemistry

2 answers:

alexira [117]2 years ago

6 0

The answer is:

K₃PO₄ (aq) → 3K⁺ (aq) + PO₄³⁻ (aq)

<h2>Further Explanation </h2>

The chemical change could be an action that always produces interchange of chemical compounds. The initial compounds or compounds involved within the reaction are called reactants. Chemical reactions are usually characterized by chemical changes and can produce one or more products that sometimes have different characteristics from reactants. Classically, chemical reactions involve changes involving the movement of electrons within the formation and breaking of chemical bonds, although the final concept of chemical reactions may be applied to the transformation of elementary particles like in nuclear reactions. Different chemical reactions are used together in chemical synthesis to provide the required compound product. In biochemistry, a series of chemical reactions catalyzed by enzymes form a metabolic pathway, where synthesis and decomposition that are normally impossible within the cell are administered.

Grouping of chemical reactions

The variety of chemical reactions and approaches employed in studying them result in many ways to classify those reactions, which frequently overlap. Below are samples of the classification of chemical reactions that are usually used.

Four basic reactions

1. Synthesis

In a direct combination reaction or synthesis, two or more simple compounds combine to create new, more complex compounds. Two or more reactants that react to provide one product is additionally the simplest way to understand if it's a synthesis reaction.

2. Decomposition

Decomposition or analysis reactions are the alternatives of synthesis reactions. A more complex compound is lessened into simpler compounds.

3. Single replacement

In a single replacement or substitution reaction, one element replaces another single element during a compound.

4. Double replacement

In a double replacement reaction, two compounds change ions or bonds to create different new compounds. This happens when the cations and anions of two different compounds move from one place to a different and form 2 new compounds.

In chemistry, the equation of a reaction or chemical equation is that the symbolic writing of a chemical change. The formula of the reagent is written to the left of the equation and also the formula of the merchandise is written to the proper. The coefficient written to the left of a formula could be a stoichiometric coefficient, which describes the number of that substance involved during a reaction relative to a different substance. The reaction equation was first made by the iatrochemist Jean Beguin in 1615. during a reaction equation, reagents and products are connected by different symbols. The symbol → is employed for one-way reactions, ⇆ for two-way reactions, and ⇌ equilibrium reactions.

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Grade: College

Subject: Chemistry

keywords: chemical equation

Anna35 [415]2 years ago

3 0

Balanced chemical reaction (dissociation): K₃PO₄(aq) → 3K⁺(aq) + PO₄³⁻(aq).
K₃PO₄ is potassium phosphate, <span>a water-soluble </span>ionic salt.
In water potassium phosphate, ionic compound, dissociates on positive potassium ion (cations) and negative phosphate ions (anions).
Potassium has positive charge (+1), compound has neutral charge.

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Calculate the pH of a solution that contains 2.7 M HF and 2.7 M HOC6H5. Also, calculate the concentration of OC6H5- in this solu

borishaifa [10]

Answer:

$\large \boxed{\mathbf{1.36; 3.6 \times 10^{\mathbf{-9}}}\textbf{mol/L}}$

Explanation:

The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.

1 .Calculate the hydronium ion concentration

We can use an ICE table to organize the calculations.

HF + H₂O ⇌ H₃O⁺ + F⁻

I/mol·L⁻¹: 2.7 0 0

C/mol·L⁻¹: -x +x +x

E/mol·L⁻¹: 2.7 - x x x

$K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}] \text{F}^{-}]} {\text{[HF]}} = 7.2 \times 10^{-4}\\\\\dfrac{x^{2}}{2.7 - x} = 7.2 \times 10^{-4}\\\\\text{Check for negligibility of }x\\\\\dfrac{2.7}{7.2 \times 10^{-4}} = 4000 > 400\\\\\therefore x \ll 2.7\\\dfrac{x^{2}}{2.7} = 7.2 \times 10^{-4}\\\\x^{2} = 2.7 \times 7.2 \times 10^{-4} = 1.94 \times 10^{-3}\\x = 0.0441\\\text{[H$_{3}$O$^{+}$]}= \text{x mol$\cdot$L$^{-1}$} = \text{0.0441 mol$\cdot$L$^{-1}$}$

2. Calculate the pH

$\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{0.0441} = \large \boxed{\mathbf{1.36}}$

3. Calculate [C₆H₅O⁻]

C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺

2.7 x 0.0441

$K_{\text{a}} = \dfrac{0.0441x} {2.7} = 1.6 \times 10^{-10}\\\\0.0441x = 1.6 \times 10^{-10}\\x = \dfrac{1.6 \times 10^{-10}}{0.0441} = \mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}\\\text{The concentration of phenoxide ion is $\large \boxed{\mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}}$}$