Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a 
b 
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:
Solving (b): Probability that none are defective.
The probability that a selection is not defective is:
For two selections, the probability that all are not defective is:
Answer:
Sorry I feel bad I don't kt the answer sorry hope you find the answer tho
Step-by-step explanation:
sorry
A) x + y = 110
x - y = 40
B) Melvin swims for 35 minutes every day.
C) It is not possible
Step-by-step explanation:
Step 1:
Let x denote the duration for which Melvin plays tennis and y denote the duration for which he swims
Step 2 :
Part A :
Given that the total duration for which he plays and tennis is 110 minutes
so we have x + y = 110
Also given that he plays tennis for 40 minutes more than he swims
So, x = y+ 40 =>x-y = 40
So the linear pair of equations are
x + y = 110
x-y = 40
Step 3 :
Part B
Solving the above 2 equations we have
y+40+y = 110 = > 2y+ 40 = 110 = > y = 2y = 70 = >35
x = y+40 = 35+ 40 = 75
So Melvin plays tennis for 75 minutes and swims for 35 minutes every day.
Step 4 :
Part C
Given he plays and swims for 110 mins exactly, i.e x + y = 110
If Melvin plays tennis for 70 minutes , then x = 70, then the time for which he can swim is 110 - 70 = 40 mins.
He gets only 40 mins for swimming which is not 40 mins more than he plays tennis .
So this case is not possible.
Answer:
there is no picture...
Step-by-step explanation:
Answer:
y = 84
Step-by-step explanation:
1) add 3 to both sides of your equation to cancel out the -3
end up with: (1/3)y + 14 = (1/2)y
2) multiply both sides of your equation by 2 to cancel out the (1/2)
end up with: (2/3)y + 28 = y
3) subtract (2/3)y from both sides of the equation to cancel out the positive (2/3)y
end up with: 28 = (1/3)y
4) multiply both sides of the equation by 3 to cancel out the (1/3)
end up with: 84 = y
