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3 years ago

Write the structures for all the isomers of the â€“C5H11 alkyl group.

Chemistry

1 answer:

seropon [69]3 years ago

5 0

Answer:

Explanation:

Alkyl groups are those which are derived from alkane by the removal of one hydrogen atom

For example ,methane CH4, and its corresponding alkyl groups is methyl -CH3

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14.A sample of fluorine gas has a density of _____

yarga [219]

Answer:

d = 0.793 g/L

Explanation:

Given data:

Density of fluorine gas = ?

Pressure of gas = 0.554 atm

Temperature of gas = 50 °C (50+273.15K = 323.15 K)

Solution:

Formula:

PM = dRT

M = molar mass of gas

P = pressure

R = general gas constant

T = temperature

d = PM/RT

d = 0.554 atm × 37.99 g/mol / 0.0821 atm.L /mol.K × 323.15 K

d = 21.05 atm.g/mol/26.53 atm.L /mol

d = 0.793 g/L

8 0

3 years ago

What happens when energy is released during atomic fission

Vesnalui [34]

Nuclear energy is called the energy obtained by the transformation of atomic nuclei, so small and heavy clusters of particles inside the atom. Nuclear energy can be produced in two ways, by cleavage or synthesis of nuclei. Heavy nuclei of radioactive elements such as uranium or plutonium, can be split into two nuclei. By splitting are released from the nucleus of neutrons that collide with other nuclei causing them to split and subsequent emission of neutrons. This is called a chain reaction. The condition calls self-sustaining nuclear reaction is slowing down neutrons. For this purpose, a special substance, called moderator. The neutrons collide with the molecules of the moderator precipitate heating speed while the moderator. The resulting heat heats the water so that a couple who drives a turbine generating electricity. Another way of producing nuclear energy is nuclear fusion, in which nuclei combine to light elements. So far, fusion, however, failed to carry out so that it can be applied to the economy as a source of energy.

4 0

3 years ago

10mL volume of 75mM EtOH is necessary for an experiment. What volumes of 1M EtOH and water should be mixed to obtain the working

kenny6666 [7]

Answer: Volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration.

Explanation:

According to the dilution law,

$C_1V_1=C_2V_2$

where,

$C_1$ = molarity of stock solution = 1M

$V_1$ = volume of stock solution = ?

$C_2$ = molarity of diluted solution = 0.075 M (1mM=0.001M)

$V_2$ = volume of diluted solution = 10 ml

Putting in the values we get:

$1M\times V_1=0.075M\times 10ml$

$V_1=0.75ml$

Thus 0.75 ml of 1M EtOH is taken and (10-0.75)ml = 9.25 ml of water is added to make the volume 10ml.

Therefore, volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration

3 0

3 years ago

Marshall determines that a gas has a gauge pressure of 276 kpa what's the absolute pressure of the gas

omeli [17]

A gauge records the pressure over atmospheric pressure (0kpa on the gauge is actually the atmospheric pressure and a reading of 276kpa is 276kpa over atmospheric pressure). That means that means that to find absolute pressure you just add atmospheric pressure (around 1atm (101kpa)) to 286kpa to get 387kpa. I hope this helps.

6 0

3 years ago

A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 192.mg of oxalic acid H2

kap26 [50]

Answer:

The molarity of the NaOH solution is 0.076 M

Explanation:

Step 1: Data given

Mass of oxalic acid = 192 mg = 0.192 grams

volume = 250 mL = 0.250 L

Molar mass oxalic acid = 90.03 g/mol

Step 2: The balanced equation

H2C2O4 + 2NaOH → Na2C2O4 + H2O

Step 3: Calculate moles of oxalic acid

Moles oxalic acid = 0.192 grams / 90.03 g/mol

Moles oxalic acid = 0.00213 moles

Step 4: Calculate molarity of oxalic acid

Molarity = Moles / volume

Molarity = 0.00213 moles / 0.250 L

Molarity = 0.00852 M

Step 5: Calculate Molarity of NaOH

2 Ca*Va = Cb*Vb

with Ca = Molarity of oxalic acid = 0.00852 M

with Va = volume of oxalic acid = 0.250 L

with Cb = Molarity of NaOH = TO BE DETERMINED

with Vb = volume of 0.0558 L

Cb = (2*0.00852 * 0.25) / 0.0558

Cb = 0.076 M

The molarity of the NaOH solution is 0.076 M

4 0

2 years ago