The explanation for the large space between particles in a gas is provided by the kinetic theory (option C).
<h3>What is the kinetic theory?</h3>
The kinetic theory is a scientific theory used in physics to understand the behavior of gases.
This theory (kinetic theory) indicates that molecular distances in gases are small when compared to the molecular sizes.
In conclusion, the explanation for the large space between particles in a gas is provided by the kinetic theory (option C).
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Answer:
Aquatic ecosystem has two components -
- Biotic components
2.Abiotic components
temperature and amount of sunlight are the part of abiotic component .
while living things like sponges and planktons are the biotic components of ecosystem.
Explanation:
aquatic components are of two types-
freshwater ecosystem( lakes and ponds, river and streams)
marine ecosystem(ocean ecosysyem, estuaries)
planktons-
planktons are found in limnetic zone, availability of sunlight is much here. planktons are zooplanktons and phytoplanktons are very important link in aquatic ecosystem.
sponges
In marine water, the <em>benthic zone</em> is the area below the<em> pelagic zone.</em> Here temperature decreased because of less light perception. This zone is very nutrient rich so organisms which are present here are- bacteria, fungi, sea anemone, sponges and some fishes.
<h2>
1.25 g of 
would be produced from the complete reaction of 25 mL of 0.833 mol/L 
with excess 
</h2>
Explanation:
To calculate the number of moles for given molarity, we use the equation:
According to stoichiometry:
1 mole of 
will give = 1 mole of
0.0208 moles of will give =
of
Mass of 
Thus 1.25 g of would be produced from the complete reaction of 25 mL of 0.833 mol/L with excess
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Answer:
16.8%
Explanation:
31% NaOH molar mass 40 gm
69% H2O molar mass 18 gm
1000 gm would be
310 gm NaOH or 310/40 = 7.75 moles
690 gm of H2O or 690/18 = 38.333 moles
7.75 / (7.75 + 38.333) = .168 mole fraction
The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M
calculation
concentration = moles /volume in liters
volume in liters = 150 /1000= 0.15 L
number of moles calculation
write the equation for dissociation of Al2Cl3
that is AlCl3 ⇔ Al^3+ + 3 Cl ^-
find the moles of Cl^- formed
moles =mass/molar mass
mass in grams= 550/ 1000 =0.55 grams
molar mass of Cl^- =35.5 g/mol
moles is therefore= 0.55/35.5 =0.0155 moles
by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles
concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M
