Answer:
275.3 nm is the wavelength of light required for mercury.
Mercury can not be used to generate electricity from the sun because wavelength at which mercury will emit an electron is smaller than 500 nm.
Explanation:
The wavelength of light required for mercury to emit an electron.
The wavelength of the radiation = 
Energy required fro mercury to to emit an electron = E
Energy required fro mercury to to emit an electron will the energy if the radiation = E' = 
E' = E
To calculate the wavelength of light, we use the equation:
where,
= wavelength of the light
h = Planck's constant = 
c = speed of light = 
Wavelength of the sun light in the visible region = 500 nm
500 nm > 275.3 nm
Less energy < more energy
So, this means that mercury can not be used to generate electricity from the sun.
Answer:
The answer to your question is simultaneous. Hope it helps!
Answer:
Explanation:
Hello there!
In this case, since the combustion of B2H6 is:
Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:
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Calcium fluoride.
Ca is metal, F is non-metal, so they form ionic bond.
Ca as metal can form only positive ion. Ca in the second group, so the charge of Ca ion is 2+. Ca²⁺
F is in the 17th group, so it has 7 electrons on the last level. It is non-metal, non-metal, so it has negative charge -(8-7)=-1. "8" because on the last level cannot be more than 8 electrons. F-ion is F¹⁻.
Ca²⁺ F¹⁻
Number of positive charges should be equal to number of negative charges,
Formula of calcium fluoride
CaF2.
2 atoms Fluorine bond with Calcium.
Answer:
carbon
Explanation:
because it is an allotrope of carbon
