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lina2011 [118]
3 years ago
11

What do you think is the effect of acid rain on rusting ?

Chemistry
1 answer:
stich3 [128]3 years ago
8 0
As acid rain is a mixture of pollutants and gasses. As rusting is a chemical reaction between oxygen and other gasses in the air alongside a material and a liquid. I would say they are both similar and that acid rain would speed the process of rusting/aid the process.
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In the ground-state electron configuration of fe3+, how many unpaired electrons are present? express your answer numerically as
Virty [35]
Answer:
            Iron has 5 unpaired electrons in Fe⁺³ state.

Explanation:

Iron having atomic number 26 has following electronic configuration in neutral state.

                             Fe =  1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d⁶

When Iron looses three electrons it attains +3 charge with following electronic configuration.

                             Fe⁺³ =  1s², 2s², 2p⁶, 3s², 3p⁶, 3d⁵

The five electrons in d-orbital exist in unpaired form as,

                          3(dz)¹, 3d(xz)¹, 3d(yz)¹, 3d(xy)¹, 3(dx²-y²)¹


3 0
3 years ago
Fritz Haber, a German chemist, discovered a way to synthesize ammonia gas (NH3) by combining hydrogen and nitrogen gases accordi
Westkost [7]
1) Write the balanced equation to state the molar ratios:

<span>3H2(g) + N2(g) → 2NH3(g)

=> molar ratios = 3 mol H2 : 1 mol N2 : 2 mol NH3

What volume of nitrogen is needed to produce 250.0 L of ammonia gas at STP?

First, convert the 250.0 L of NH3 to number of moles at STP .

Use the fact that 1 mole of gas at STP occupies 22.4 L

=> 250.0 L * 1mol/22.4 L = 11.16 L

Second, use the molar ratio to find the number of moles of N2 that produces 11.16 L of NH3

=> 11.16 L NH3 * [1 mol N2 / 2 mol NH3] = 5.58 mol N2

Third, convert 5.58 mol N2 into liters at STP

=> 5.58 mol N2 * [22.4 L/mol] = 124.99 liters

Answer: 124,99 liters

What volume of hydrogen is needed to produce 2.50 mol NH3 at STP?
 

First, find the number of moles of H2 that produce 2.50 mol by using the molar ratios:

2.50 mol NH3 * [3mol H2 / 2 mol NH3] = 3.75 mol H2

Second, convert the number of moles to liters of gas at STP:

3.75 mol * 22.4 L/mol =  84 liters of H2

Answer: 84 liters

 </span>



6 0
3 years ago
Read 2 more answers
All matter has thermal energy because atoms are constantly
ololo11 [35]
The atoms are constantly in motion
3 0
3 years ago
The solubility of KClO3(s) in water increases as the
algol [13]
<span>Answer: option (1) solubility of the solution increases.
</span><span />

<span>Justification:
</span><span />

<span>The solubility of substances in a given solvent is temperature dependent.
</span><span />

<span>The most common behavior of the solubility of salts in water is that the solubiilty increases as the temperature increase.
</span><span />

<span>To predict with certainty the solubility at different temperatures you need the product solubility constants (Kps), which is a constant of equlibrium of the dissolution of a ionic compound slightly soluble in water, or a chart (usually experimental chart) showing the solubilities at different temperatures.
</span><span />

<span>KClO₃ is a highly soluble in water, so you do not work with Kps.
</span><span />

<span>You need the solubility chart or just assume that it has the normal behavior of the most common salts. You might know from ordinary experience that you can dissolve more sodium chloride (table salt) in water when the water is hot. That is the same with KClO₃.


</span><span>The solubility chart of KlO₃ is almost a straight line (slightly curved upward), with positive slope (ascending from left to right) meaning that the higher the temperature the more the amount of salt that can be dissolved.</span>
4 0
3 years ago
Read 2 more answers
Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess
Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

Explanation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The relation of K_c\& K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p= Equilibrium constant in terms of partial pressure.=98.1

K_c= Equilibrium constant in terms of concentration  =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

\Delta n_g = Difference between gaseous moles on product side and reactant side=n_{g,p}-n_{g.r}=1-2=-1

98.1=K_c(RT)^{-1}

98.1 =\frac{K_c}{RT}

K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

5 0
3 years ago
Read 2 more answers
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