A sample of ideal gas at room temperature occupies a volume of 12.0 L at a pressure of 802 torr . If the pressure changes to 401
0 torr , with no change in the temperature or moles of gas, what is the new volume, V 2 ?
1 answer:
The new volume is 2.4 L
<u><em> calculation</em></u>
The new volume is calculated using Boyle's law formula
That is P₁V₁=P₂V₂
where,
p₁ = 802 torr
V₁ = 12.0 l
P₂ = 4010 torr
V₂=?
make V₂ the subject of the formula by diving both side of equation by P₂
V₂ = P₁V₁/P₂
V₂ is therefore = {(12.0 l × 802 torr) 4010 torr} = 2.4 L
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