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3 years ago

Number 26 I don't get it

Mathematics

1 answer:

Alexxx [7]3 years ago

3 0

All you have to do is simplify them together, just like you would any equation

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Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Mkey [24]

For this case, we have to:

By definition, we know:

The domain of $f (x) = \sqrt [3] {x}$ is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

$y = \sqrt [3] {x-2}$ with $x = 0$ : $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x+2}$ with $x = 0:\ y = \sqrt [3] {2}$ is also defined.

$f (x) = \sqrt {x}$ has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x+2}$ if it is defined for $x = 0$ .

Answer:

$y = \sqrt {x-2}$

Option b

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3 years ago

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Svetach [21]

Answer:

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If two sides of a triangle are 9cm and 15cm in length, which COULD be the measure of the third side?

MArishka [77]

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max2010maxim [7]

Answer:

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Step-by-step explanation:

12u and -uv both have a factor of u in common, so we can pull it out to give us the factored expression u(12-v).

Note on factoring:

Remember, it's just using the distributive property in reverse! We can get our original expression back by distributing the u to the 12 and the -v.

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3 years ago

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