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sukhopar [10]
3 years ago
12

Polarity occurs in which type of bond? covalent ionic metallic negative

Chemistry
2 answers:
marysya [2.9K]3 years ago
4 0
Covalent bonds is when polarity is formed
Masteriza [31]3 years ago
4 0

Answer: Option (b) is the correct answer.

Explanation:

When there is transfer of electrons between two atoms then it results in the formation of ionic bonds.

Ionic bonds have opposite charges on its atoms and are strongly held by attractive forces. Therefore, polarity is induced in ionic compounds also due to difference in electronegativity of the two atoms.

Thus, we can conclude that polarity occurs in ionic type of bond.

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1) Consider this row in the periodic table. What changes can you predict based on what information is provided by the boxes for
bearhunter [10]

Answer:

B) As you move across the row, the number of electrons increases and reactivity also increases.

Explanation:

The periodic table is arranged in a way that if you go across a period, the number of protons, neutrons, and electrons in an element increases. In terms of reactivity, the most reactive elements are the ones which have a high electronegativity. The electronegativity of the elements increases as you travel to the right and upwards on the periodic table.

4 0
2 years ago
1. Alexa and her family travelled 5 hours south east on 1-45 to crystal
Gre4nikov [31]

Answer:

Average speed  = 68 mph

Explanation:

Given that,

Total distance traveled by the family, d = 340 miles

The family traveled 5 hours southeast.

We need to find her average speed. The speed of an object is given by the total distance covered divided by time taken. So,

v=\dfrac{d}{t}

Put all the values,

v=\dfrac{340}{5}\\\\v=68\ mph

So, her average speed is equal to 68 mph.

5 0
3 years ago
Draw the most stable resonance structure for the intermediate in the electrophilic aromatic bromination of aniline, anisole, and
ASHA 777 [7]

Answer:

Here's what I get

Explanation:

(a) Intermediates

The three structures below represent one contributor to the resonance-stabilized intermediate, in which the lone pair electrons on the heteroatom are participating (the + charge on the heteroatoms do not show up very well).

(b) Relative Stabilities

The relative stabilities decrease in the order shown.

N is more basic than O, so NH₂ is the best electron donating group (EDG) and will best stabilize the positive charge in the ring. However, the lone pair electrons on the N in acetanilide are also involved in resonance with the carbonyl group, so they are not as available for stabilization of the ring.

(c) Relative reactivities

The relative reactivities would be

C₆H₅-NH₂ >  C₆H₅-OCH₃ > C₆H₅-NHCOCH₃

4 0
3 years ago
Sound wave a has lower frequency than sounds wave b but both waves have the same amplitude . What must also be true of these two
Nady [450]

Explanation:

Higher the frequency smaller will be the wavelength. Higher frequency have shorter wavelength and lower frequency waves have larger wavelength. Also, Beats are formed by the superposition of two waves with slightly different frequencies but with similar amplitudes. In time, waves switch between constructive interference and disruptive interference, giving the resultant wave a time-varying amplitude.

8 0
3 years ago
Read 2 more answers
The alkali earth metal beryllium (Be) engages in a chemical reaction and loses all of its valence electrons.
denpristay [2]

The loss of electron from an results in the formation of cation represented by the positive charge on the element whereas gaining of electron results in the formation of anion represented by the negative charge on the element.

The alkali earth metal beryllium (Be) belongs to the second group of the periodic table. The ground state electronic configuration of Be is:1s^{2}2s^{2}

From the electronic configuration it is clear that it has 2 valence electrons in its valence shell (2s^{2}).

After losing all valence electrons that is 2 electrons from 2s orbital. The electronic configuration will be:

1s^{2}2s^{0}

Since, lose of electron is represented by positive charge on the element symbol. So, the beryllium will have +2 charge on its symbol as Be^{2+}.

Hence, beryllium will have 2+ charge on it after losing all its valence electrons in the chemical reaction.

6 0
3 years ago
Read 2 more answers
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