An electromagnet produces mechanical energy from Electrical energy.
D. All the three bulbs connected in the series circuit will burn at equal brightness.
<h3>What is series circuit?</h3>
A series circuit comprises a path along which the whole current flows through each component.
A parallel circuit comprises branches so that the current divides and only part of it flows through any branch.
In a series circuit, same current flows in each component of the circuit.
V = I(R₁ + R₂ + R₃)
where;
- R₁ is resistance of bulb 1
- R₂ is resistance of bulb 2
- R₃ is resistance of bulb 3
If all the bulbs have equal resistance, they will burn at equal brightness.
Thus, all the three bulbs connected in the series circuit will burn at equal brightness.
The correct option is D.
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Answer:
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
Explanation:
u = Object distance
v = Image distance
f = Focal length = 35
m = Magnification = 2.5
Lens equation
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
<u>Given:</u>
Temperature T = 0.20 μK
<u>To determine:</u>
The de Broglie wavelength of Rubidium atoms
<u>Explanation:</u>
The de broglie wavelength (λ) is related to the temperature (T) as:
λ = h/√2πmkT -----(1)
where h = Planck's constant = 6.626*10⁻³⁴ Js
m = mass of Rubidium = 85.47 amu * 1.66*10⁻²⁷ kg/ 1 amu = 1.419*10⁻²⁵ kg
k = Boltzmann constant = 1.38*10⁻²³ J.K⁻¹
T = temperature = 0.2 μK = 0.2 *10⁻⁶ K
Substituting these values in equation (1) we get:
λ = 6.626*10⁻³⁴ Js/√2π * 1.419*10⁻²⁵ kg * 1.38*10⁻²³ J.K⁻¹ * 0.2 *10⁻⁶ K
= 4.224*10⁻⁷ m
Ans: The de Broglie wavelength is 4.224*10⁻⁷ m