Answer:
If the angular acceleration is a constant A, then this constant times the time will be equal to the angular velocity.
We know that after accelerating for 10 seconds, the angular velocity is 0.4 rad/s
Then:
A*10s = 0.4 rad/s
If we solve this for A we get:
A = (0.4 rad/s)/10s = 0.04 rad/s^2
This is the angular acceleartion.
Now we assume that the angular speed remains constant at 0.4 rad/s, and we know that the radius of the carousel is 20m, we want to find the linear velocity of the children.
We know that for an angular velocity W and for a radius R, the linear velocity is:
V = R*W
Then in this case the linear velocity is:
V = 20m*(0.4 s^(-1)) = 8 m/s
Answer:
it will have a speed of 10ms after 1 second
Answer:
If magnitude of vector A is less than magnitude of vector B then its x-component will be also less
Explanation:
In first case magnitude can never be negative -ve sign shows the direction only so it is incorrect statement.
The magnitude of any vector can never be less than its component because component of vector is found with the multiplication of sine and cos angle which values lies between 0 and 1 so after multiplication it gives less value than the vector
If magnitude of any vector is less then its x component will also be less because magnitude of component is dependent on the magnitude of vector
Weight is equal to the mass of the object times the acceleration due to gravity (which is 9.8
on earth)
So W=mg
W=10.0 × 9.8 = 98
So the weight is 98N.
Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.
Explanation:
- Let <em>S</em> be the speed of the swimmer, given as 1.25 m/s
- Let
be the speed of the river's current given as 1.00 m/s.
- Note that this speed is the magnitude of the velocity which is a vector quantity.
- The direction of the swimmer is upstream.
Hence the resultant velocity is given as, 
= S — S 0
= 1.25 — 1
= 0.25 m/s.
Therefore, the observing friend will see the swimmer moving at a speed of 0.25 m/s due to resistance produced by the current of the river.
