A small, single engine airplane is about to take off. The airplane becomes airborne, when its speed reaches 193.0 km/h. The cond itions at the airport are ideal, there is no wind. When the engine is running at its full power, the acceleration of the airplane is 2.80 m/s2. What is the minimum required length of the runway
1 answer:
Answer:
513 m
Explanation:
We have;
final speed of the airplane = 193.0 km/h * 1000/3600 = 53.6 m/s
acceleration of the air plane = 2.80 m/s2
initial velocity of the airplane = 0 m/s
length of the runway = distance covered
v^2 = u^2 + 2as
v^2 - u^2 = 2as
s = v^2 - u^2/2a
s = (53.6)^2 - 0^2/ 2 * 2.80
s = 2872.96/ 5.6
s = 513 m
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I just solved similar type of question. You can refer to my solution which I have attached