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3 years ago

A shipping carton is in the shape of a triangular prism. How many cubic inches

Mathematics

1 answer:

olga55 [171]3 years ago

7 0

Answer: 90 inches

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Volume of a rectangular prism =area of the base x length

Area of the base is the area of a triangle:

Area of a triangle = base x height x 1/2

Replacing with the values given:

A = 4 x 3 x 1/2 = 6 in2

Back on the volume formula:

V = A x h = 6 x 15 = 90 cubic inches

Feel free to ask for more if needed or if you did not understand something.

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(3 + 4i) - (8 -5i) Write answer in standard form a +bi Group of answer choices

Anton [14]

Answer:

$A=-5+9i$

Step-by-step explanation:

$\left(3+4i\right)-\left(8-5i\right)\\\\\mathrm{Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number}\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\\\=\left(3-8\right)+\left(4+5\right)i\\3-8=-5\\4+5=9\\\\=-5+9i$

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3 years ago

7. Identify the appropriate mixed number for the picture shown.

guapka [62]

The answer for this question is D because you have 2 full squares and then one half of square so 2 1/2.

5 0

2 years ago

rancho middle school has an average of 23 3/8 students per teacher write this mixed number as a decimal

Reika [66]

let's firstly convert it to an improper fraction.

$\bf \stackrel{mixed}{23\frac{3}{8}}\implies \cfrac{23\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{187}{8}}\implies 187\div 8\implies \stackrel{decimal}{23.375}$

6 0

3 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: <em>rational equation fraction solution algebra</em>

7 0

2 years ago

Can someone please help me

gavmur [86]

You can use photo math

8 0

2 years ago

Read 2 more answers