Cesium-137 has a half-life of 30 years. You find a sample with 3 g of cesium-137. How much cesium-137 existed in the sample 90 y
1 answer:
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Answer: Theoretical yield of produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of produce = 3 moles of
Thus 0.28 moles of will produce=
of
Mass of
Thus theoretical yield of produced by 8.96 g of S is 33.6 g