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Feliz [49]
2 years ago
10

A multi-nutrient fertilizer contains several different nitrogen containing compounds. The fertilizer is 53.2% CH4N2O (urea), 24.

1% KNO3 , and 11.8% (NH4)2HPO4 by mass. The remainder of the fertilizer consists of substances that do not contain nitrogen. How much fertilizer should someone apply to provide 2.20g N to a plant?
Chemistry
1 answer:
maks197457 [2]2 years ago
3 0

Answer:

7.19g of fertilizer are required to provide 2.20g of N to a plant

Explanation:

In 100g of fertilizer, the amount of nitrogen could be obtained as follows using the ratio of molar mass of nitrogen*atoms of nitrongen / molar mass of the molecule:

CH4N2O = 53.2g * (14g/mol*2 / 60.06g/mol) = 24.8gN

KNO3 = 24.1g * (14g/mol*1 / 101.10g/mol) = 3.3g N

(NH4)2HPO4 = 11.8g * (14g/mol*2 / 132.06g/mol) = 2.5g N

The mass of nitrogen in 100g of fertilizer is 24.8g + 3.3g + 2.5g = 30.6g N

That is: 30.6g N / 100g of fertilizer.

To obtain 2.20g of nitrogen are required:

2.20g N * (100g Fertilizer / 30.6g N) =

<h3>7.19g of fertilizer are required to provide 2.20g of N to a plant</h3>
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How many molecules are in 145.5 grams of Be(OH)2
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Answer:

2.04 x 10²⁴ molecules

Explanation:

Given parameters:

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To calculate the number of molecules in this mass of Be(OH)₂ we follow the following steps:

>> Calculate the number of moles first using the formula below:

Number of moles = mass/molarmass

Since we have been given the mass, let us derive the molar mass of Be(OH)₂

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>>> We know that a mole is the amount of substance that contains Avogadro’s number of particles. The particles can be atoms, molecules, particles etc. Therefore we use the expression below to determine the number of molecules in 3.38mol of Be(OH)₂:

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Number of molecules= 3.38 x 6.02 x 10²³

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2 years ago
How many moles are in 1.05 g of gold (Au)?
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