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svetlana [45]
3 years ago
10

For f(x)= 6x-5 and g(x)=5x^2-4 find the following: (fog) (x)=

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
6 0
<span>f(x)= 6x-5 and g(x)=5x^2-4
(fog) (x)= 6(g) - 5
               6(5x^2 - 4) - 5
               30x^2 - 24 - 5
               30x^2 - 29</span>
kozerog [31]3 years ago
5 0
I hope this helps you

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8n = -3m + 1; n = -2, 2, 4
bogdanovich [222]

I am assuming you want to solve for m in each case

8n = -3m + 1

8(-2) = -3m + 1

-16 = -3m + 1

-3m = -17

m = \frac{17}{3}

8(2) = -3m + 1

16 = -3m + 1

-3m = 15

m = -5

8(4) = -3m + 1

32 = -3m + 1

-3m = 31

m = \frac{31}{3}

8 0
3 years ago
Read 2 more answers
If RSTU is a rhombus, find the measure of angle RUT.
Schach [20]

<u>Finding x:</u>

We know that the diagonals of a rhombus bisect its angles

So, since US is a diagonal of the given rhombus:

∠RUS = ∠TUS

10x - 23 = 3x + 19                      [replacing the given values of the angles]

7x - 23 = 19                                [subtracting 3x from both sides]

7x = 42                                       [adding 23 on both sides]

x = 6                                           [dividing both sides by 7]

<u>Finding ∠RUT:</u>

We can see that:

∠RUT = ∠RUS + ∠TUS

<em>Since we are given the values of ∠RUS and ∠TUS:</em>

∠RUT = (10x - 23) + (3x + 19)

∠RUT = 13x - 4

<em>We know that x = 6:</em>

∠RUT = 13(6)-  4

∠RUT = 74°

8 0
3 years ago
Please need help I will be MARKING as BRIANILIST. thank you so much. ​​
ryzh [129]

Answer:

C

Step-by-step explanation:

I am guessing that's it.

8 0
3 years ago
Read 2 more answers
What is the equation written in vertex from of a parabola with a vertex of (4, –2) that passes through (2, –14)?
vichka [17]

Answer:

y = -3(x - 4)² - 2

Step-by-step explanation:

Given the vertex, (4, -2), and the point (2, -14):

We can use the vertex form of the quadratic equation:

y = a(x - h)² + k

Where:

(h, k) = vertex

a  =  determines whether the graph opens up or down, and it also makes the parent function <u>wider</u> or <u>narrower</u>.

  • <u>positive</u> value of a = opens <u><em>upward</em></u>
  • <u>negative</u> value of a = opens <u><em>downward</em></u>
  • a is between 0 and 1, (0 < a < 1) the graph is <u><em>wider</em></u> than the parent function.
  • a > 1, the graph is <u><em>narrower</em></u> than the parent function.

<em>h </em>=<em> </em>determines how far left or right the parent function is translated.

  • h = positive, the function is translated <em>h</em> units to the right.
  • h = negative, the function is translated |<em>h</em>| units to the left.

<em>k</em> determines how far up or down the parent function is translated.

  • k = positive: translate <em>k</em> units <u><em>up</em></u>.
  • k = negative, translate <em>k</em> units <u><em>down</em></u>.

Now that I've set up the definitions for each variable of the vertex form, we can determine the quadratic equation using the given vertex and the point:

vertex (h, k): (4, -2)

point (x, y): (2, -14)

Substitute these values into the vertex form to solve for a:

y = a(x - h)² + k

-14 = a(2 - 4)²  -2

-14 = a (-2)² -2

-14 = a4 + -2

Add to to both sides:

-14 + 2 = a4 + -2 + 2

-12 = 4a

Divide both sides by 4 to solve for a:

-12/4 = 4a/4

-3 = a

Therefore, the quadratic equation inI vertex form is:

y = -3(x - 4)² - 2

The parabola is downward-facing, and is vertically compressed by a factor of -3. The graph is also horizontally translated 4 units to the right, and vertically translated 2 units down.

Attached is a screenshot of the graph where it shows the vertex and the given point, using the vertex form that I came up with.

Please mark my answers as the Brainliest, if you find this helpful :)

8 0
3 years ago
HELP PLZ When x = -2, which of the following points is on the graphed line y = -4x + 3?
trapecia [35]

y = f(x) =  - 4x + 3 \\ \Rightarrow f( - 2) =  - 4( - 2) + 3 = 8 + 3 = 11 \\ \Rightarrow ( - 2,11)

6 0
3 years ago
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