Which of the following excerpts from the story does NOT help create suspense?

What is the speed at which molecules or atoms move dependent on temperature and state of matter?

Helga [31]

Kinetic energy is the speed at which molecules or atoms move dependent on the temperature and state of matter

3 0

4 years ago

** GIVEN THE BRAINLIEST** IF CORRECT!!

Drupady [299]

Answer is: The zooplankton can be used to help control algal growth in some coral communities.

Hypothesis is a suggested explanation for an observable phenomenon.

Steps of the scientific method:

1) ask a question about something that is observed.

2) do background research.

3) construct a hypothesis, an attempt to answer questions with an explanation that can be tested. In this example, does the presence of a certain type of zooplankton inhibited the algae growth

4) test of hypothesis.

5) analyze collected data and draw a conclusion. In this example, the zooplankton can be used to help control algal growth.

5 0

4 years ago

6. You have a sample of H2Ois, with a mass 23.0 grams at a temperature of 46.0

anygoal [31]

Answer: I think it would be -23

Explanation:

3 0

3 years ago

How many grams are in 0.21mol sample of ethyl alcohol?

vampirchik [111]

Mass = moles x molar mass
Molar mass of eythl alcohol = 46

Mass= 0.21 x 46= 9.66g

7 0

4 years ago

The osmotic pressure of an aqueoussolution of urea at 300 K is

den301095 [7]

<u>Answer:</u> The freezing point of solution is -0.09°C

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=imRT$

where,

$\pi$ = osmotic pressure of the solution = 120 kPa

i = Van't hoff factor = 1 (for non-electrolytes)

m = concentration of solute in terms of molality = ?

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of the solution = 300 K

Putting values in above equation, we get:

$120kPa=1\times m\times 8.31\text{ L kPa }mol^{-1}K^{-1}\times 300K\\\\m=0.05m$

To calculate the depression in freezing point, we use the equation:

$\Delta T=i\times K_f\times m$

where,

i = Vant hoff factor = 1 (for non-electrolytes)

$K_f$ = molal freezing point depression constant = 1.86°C/m

m = molality of solution = 0.05 m

Putting values in above equation, we get:

$\Delta T=1\times 1.86^oC/m\times 0.05m\\\\\Delta T=0.09^oC$

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

The equation used to calculate freezing point of solution is:

$\Delta T=\text{freezing point of water}-\text{freezing point of solution}$

where,

$\Delta T$ = Depression in freezing point = 0.09 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

$0.09^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-0.09^oC$

Hence, the freezing point of solution is -0.09°C

4 0

3 years ago