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Serhud [2]
3 years ago
6

Determine the concentration of a solution prepared by diluting 20.0 ml of a 0.200 m rbcl to 250.0 ml. determine the concentratio

n of a solution prepared by diluting 20.0 ml of a 0.200 m rbcl to 250.0 ml. 0.00800 m 0.160 m 0.0160 m 0.0320 m 2.50 m
Chemistry
1 answer:
pogonyaev3 years ago
5 0
When dealing with making diluted solutions from concentrated solutions, we can use the following formula 
c1v1 = c2v2 
where c1 and v1 are the concentration and volume of the concentrated solution respectively.
c2 and v2 are the concentration and volume of the diluted solution respectively 
substituting these values in the above formula,
20 mL x 0.200 M = C x 250.0 mL 
C = 0.0160 M 
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Mariulka [41]
The formula used for determining gas pressure, volume and temperature interaction would be PV=nRT. 

<span>• What is the temperature in Kelvins?
</span>You already right at this part. Kelvin temperature formula from celsius should be:
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It is important to remember that the formula in this question is using Kelvin unit at temperature, not Celcius or Fahrenheit.
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<span>• Assuming that everything else remains constant, what will happen to the pressure if the temperature decreases to -15 ºC?
</span>In this case, the temperature is decreased from 27C into -15C and you asked the change in the pressure.
Using PV=nRT formula, you can derive that the temperature will be directly related to pressure. If the temperature decreased, the pressure will be decreased too. 

<span> If you increase the number of moles to 6 moles, increase temperature to 400K and reduce the volume to 25 L, what will the new pressure be?
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Answer:

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Sn: 77.6 at%

Explanation:

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<em />

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Composition in at%:

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Sn: 0.5602mol / 0.7219mol × 100 = <em>77.6 at%</em>

<em />

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