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Oksana_A [137]
3 years ago
11

Salt and water are mixed together in a bowl. The salt dissolves. The bowl of salty water is left out on the table. After a few d

ays you know this that the water is gone in that the ball is covered in salt what can you conclude?
1) Salt in water are an element

2) Salt and water are a molecule

3) Salt and water are a mixture

4)Salt and water are a compound
Chemistry
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer: its either 3 or 4 kid

Explanation:

i dont think i need to say why T^T

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Please only answer if you're going to help.
ololo11 [35]

Answer:

1.solvent

2.unsoluble

3.solute

4.solvent

5.souble

6.aqueous

3 0
3 years ago
What is the value of 100 ºC on the Kelvin scale
KIM [24]
<span>Boiling point- 100 ℃, or <span>373.15K</span></span>
6 0
3 years ago
Much to everyone’s surprise, nitrogen monoxide (NO) has been found to act as a neurotransmitter. To prepare to study its effect,
SVEN [57.7K]

Answer: 0.0043mole

Explanation:Please see attachment for explanation

3 0
4 years ago
If you only have 36.5 grams of Potassium Carbonate (K2CO3 molar mass = 138.2 g/mole). How many liters of a 0.52 M solution can y
kirza4 [7]

Answer:

0.508 L of solution.

Explanation:

Always a safe bet to convert to moles:

n= {m \over MM}\\

Where n is moles, m is mass, and MM is molar mass.

Now remember the equation for concentration (molarity):

C={n \over V}

Where C is the concentration, n is moles, and V is volume.

To make this easy, combine the two equations (note n appears in both, so you can do a substitution) and solve for V as the question asks:

C={m \over MM \times V}\\0.52={36.5 \over 138.2 \times V}\\V={36.5 \over 138.2 \times 0.52}\\V=0.508

Therefore we can make 0.508 L of solution.

8 0
3 years ago
A food is initially at a moisture content of 90% dry basis. Calculate the moisture content in wet basis
Anvisha [2.4K]

Answer:

Moisture content in wet basis = 47.4 %    

Explanation:

<u>Moisture content expresses the amount of water present in a moist sample.</u> <u>Dry basis and wet basis are widely used to express moisture content.   </u>

The next equation express the moisture content in wet basis:  

                MC_{wb}=\frac{MC_{db}}{1+MC_{db}}

<em>where,  MC_{wb}: moisture content in wet basis and  </em>

<em>              MC_{db}: moisture content in dry basis    </em>

We now calculate the moisture content in wet basis:

MC_{wb}=\frac{MC_{db}}{1+MC_{db}}

MC_{wb}=\frac{0.90}{1+0.90}

MC_{wb}= 0.474 = 47.4 % wet basis    

Have a nice day!

8 0
4 years ago
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