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Oksana_A [137]
3 years ago
11

Salt and water are mixed together in a bowl. The salt dissolves. The bowl of salty water is left out on the table. After a few d

ays you know this that the water is gone in that the ball is covered in salt what can you conclude?
1) Salt in water are an element

2) Salt and water are a molecule

3) Salt and water are a mixture

4)Salt and water are a compound
Chemistry
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer: its either 3 or 4 kid

Explanation:

i dont think i need to say why T^T

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PLEASE HELP!!
NARA [144]
We can skip option B and D because NaCl is salt and H₂SO₄ is a strong acid.
Neutralization reactions are those reactions in which acid and base react to form salt and water.
As water being amphoteric in nature can react with HCl as follow,

                           HCl  +  H₂O   ⇆  H₃O⁺  +  OH⁻

In this case no salt is formed, so we can skip this option.

Ammonia being a weak base can abstract proton from HCl as follow,

                              HCl  +  NH₃  →  NH₄Cl

Ammonium Chloride is a salt. So, among all four options, Option-C is the correct answer.
3 0
3 years ago
Read 2 more answers
Balance NO + 02 -- NO2 ​
Simora [160]

Answer:

NO + O2 -> NO2

it is balanced

3 0
3 years ago
Which two organ systems work together to provide cells with oxygen and to remove carbon
-BARSIC- [3]

Answer:

Lungs

Explanation: The two organ systems that work together to provide the cells with oxygen and remove carbon dixoide from the body are the lungs.

3 0
3 years ago
What is the process of using one or more of your five senses to measure or collect data?
sveta [45]

Answer:

B no observation pls mark me branilest

7 0
3 years ago
Read 2 more answers
13.3 g of benzene (C6H6) is dissolved in 282 g of carbon tetrachloride. What is the molal concentration of benzene in this solut
Verizon [17]

Answer:

0.605 molal

Explanation:

molality is the amount of solute in a particular mass of solvent.

lets calculate the amount of benzene solute.

mass of benzene= 13.3g

molar mass of C6H6= 12*6 +1*6 =72+7=78g/mol

amount of benzene= mass/molar mass

                           =13.3/78

                          =0.1705mol

molality= amount of solute/mass of solvent in kg

mass of solvent=282g=0.282kg

molality = 0.1705/0.282

    =0.605 molal

6 0
3 years ago
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