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Taya2010 [7]
3 years ago
10

Out of the 400 students in a final year in secondary school, 300 are offering biology and 190 are offering chemistry. I) how man

y student are offering both subject , if only 70 students are offering neither biology nor chemistry? I) how many students are offering at least one biology and chemistry?
Mathematics
1 answer:
iren2701 [21]3 years ago
4 0

Answer:

I) how many student are offering both subject , if only 70 students are offering neither biology nor chemistry?

= 160 students

II) how many students are offering at least one biology and chemistry?

= 330 students

Step-by-step explanation:

I) how many student are offering both subject , if only 70 students are offering neither biology nor chemistry?

Total number of student n ( B ∪ C) = 400

Students offering biology n(B) = 300

Students offering chemistry n(C) = 190

Students not offering biology nor chemistry = 70

Students offering both biology and chemistry n ( B ∩ C) = ??

n ( B ∪ C) - Students neither offering biology nor chemistry = n(B ) + n ( C ) - n ( B ∩ C)

400 - 70 = 300 + 190 - n ( B ∩ C)

330 = 490 - n ( B ∩ C)

n ( B ∩ C) = 490 - 330

n ( B ∩ C) = 160

Therefore, students offering both Biology and Chemistry are 160 students.

II) how many students are offering at least one biology and chemistry?

n(B' ) + n ( C') + n ( B ∩ C)

n(B') = Students offering biology only

= n(B) - n ( B ∩ C)

= 300 - 160 = 140

n(C') = Students offering chemistry only

n(C) - n ( B ∩ C)

= 190 - 160

= 30

(300 - 160) + (190 - 160) + 160

140 + 30 + 160

= 330 students

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Urgent help, please!.....
pishuonlain [190]

To solve this problem, we want to get all of the possible options into the same form, so that it is easier to compare them. Personally, I prefer comparing in decimals, so that is how I am going to solve this problem.


13/4 - To turn this improper fraction into its decimal equivalent, it is easier to first turn it into a mixed number by dividing the numerator by the denominator.

13/4 = 3 1/4

Because we know that 1/4 = 0.25, we now know that 3 1/4 = 3.25

Therefore, 13/4 = 3.25


3 1/2 - This is similar to the end of the process above. We know that 1/2 = 0.5, so we know that 3 1/2 = 3.5

3 1/2 = 3.5


3.15 is already in its decimal form, so we can leave that be for now.


√9 - To simplify this, we must figure out what number multiplied by itself equals 9. If we start with 2 (2*2 = 4), so that is too small. Next maybe we try 4 (4 * 4 = 16), so that is too large. Now we know we need a number in between 2 and 4, so maybe we try 3. 3 * 3 = 9, so we can conclude that √9 = 3.

√9 =3


If we take all of our decimal equivalents, we have 3.25, 3.5, 3.15, and 3.


Because all of these values have the same whole number value of 3, we need to compare the decimals to find out what order they belong in.


Our final order is (from smallest to largest): 3, 3.15, 3.25, 3.5


But, we need to substitute in the equivalent values we were given for these decimals originally to finish the problem.


This makes your final answer: √9, 3.15, 13/4, 3 1/2


Hope this helps!

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