To find the mass of glucose, you must multiply the atomic weight of each of the elements in the molecule by the subscripts in the formula:



Then you add all of them together:

Therefore, the molar weight of glucose is 180.15 grams.
Answer : 13.64 mL
Explanation : The reaction requires 13.64 mL of NaOH
From the reaction we know that oxalic acid requires two moles of NaOH so we have to calculate the number of moles of both.
0.150 L X 0.1500 moles/L = 2.25 X 
So the moles of NaOH will be 2 X (2.25 X
) = 4.5 X 
Now, we know the concentration of NaOH as 0.330 M
4.5 X
moles / 0.330 moles/L = 0.01364 L or 13.64 mL
So, the volume of NaOH needed to neutralize oxalic acid will be 13.64 mL
Answer:
I don't get it is it even a question?
Answer:a) 2C4H10 + 13O2 —> 8CO2 + 10H2O. Oxidation reaction
b) 8 (4 moles CO2 per mole butane)
Explanation:
could be written C4H10 + 6 1/2 O2 —> 4CO2 + 5H2O