The best answer is no bc the question ask "Would the two as yet undiscovered element A+1 and D+2" don't sound right
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Answer:
Inflamabilidad y características de la llama: el hidrógeno es inflamable en el aire en un amplio rango de concentraciones y arde, en ausencia de impurezas, con una llama casi invisible. Energía de ignición: el hidrógeno puede entrar en ignición con una cantidad de energía muy pequeña.
Explanation:
espero te sirva✍️
Answer:
9.368g/mL
Explanation:
The density is defined as the mass of a compound in a determined volume.
Based on Archimedes' law, the volume of the piece of metal is the difference between the volume of the water + the inmersed piece - the original volume of water. That is:
<em>Volume of the metal:</em>
257.5mL - 229.0mL = 28.5mL
As the mass of the metal is 267.0g; its density is:
<em>Density:</em>
267.0g / 28.5mL =
<h3>9.368g/mL</h3>
Answer:
![\boxed {\boxed {\sf About 7.1 \ mol \ H_2O}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20About%207.1%20%5C%20mol%20%5C%20H_2O%7D%7D)
Explanation:
To convert from molecules to moles, we must use Avogadro's Number: 6.022*10²³. This tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are molecules of water.
![\frac {6.022*10^{23} \ molecules \ H_2O} {1 \ mol \ H_2O}](https://tex.z-dn.net/?f=%5Cfrac%20%7B6.022%2A10%5E%7B23%7D%20%5C%20molecules%20%5C%20H_2O%7D%20%7B1%20%5C%20mol%20%5C%20H_2O%7D)
Multiply by the given number of molecules.
![4.3 *10^{24} \ molecules \ H_2O *\frac {6.022*10^{23} \ molecules \ H_2O} {1 \ mol \ H_2O}](https://tex.z-dn.net/?f=4.3%20%2A10%5E%7B24%7D%20%5C%20molecules%20%5C%20H_2O%20%2A%5Cfrac%20%7B6.022%2A10%5E%7B23%7D%20%5C%20molecules%20%5C%20H_2O%7D%20%7B1%20%5C%20mol%20%5C%20H_2O%7D)
Flip the fraction so the molecules of water cancel.
![4.3 *10^{24} \ molecules \ H_2O *\frac {1 \ mol \ H_2O} {6.022*10^{23} \ molecules \ H_2O}](https://tex.z-dn.net/?f=4.3%20%2A10%5E%7B24%7D%20%5C%20molecules%20%5C%20H_2O%20%2A%5Cfrac%20%7B1%20%5C%20mol%20%5C%20H_2O%7D%20%7B6.022%2A10%5E%7B23%7D%20%5C%20molecules%20%5C%20H_2O%7D)
![4.3 *10^{24} *\frac {1 \ mol \ H_2O} {6.022*10^{23} }](https://tex.z-dn.net/?f=4.3%20%2A10%5E%7B24%7D%20%20%2A%5Cfrac%20%7B1%20%5C%20mol%20%5C%20H_2O%7D%20%7B6.022%2A10%5E%7B23%7D%20%7D)
![\frac {4.3 *10^{24}\ mol \ H_2O} {6.022*10^{23} }](https://tex.z-dn.net/?f=%5Cfrac%20%7B4.3%20%2A10%5E%7B24%7D%5C%20mol%20%5C%20H_2O%7D%20%7B6.022%2A10%5E%7B23%7D%20%7D)
![7.140484889 \ mol \ H_2O](https://tex.z-dn.net/?f=7.140484889%20%5C%20mol%20%5C%20H_2O)
The original measurement of atoms has 2 significant figures ( 4 and 3), so our answer must have the same. For the moles we calculated, that is the tenth place. The 4 in the hundredth place tells us to leave the 1.
![7.1 \ mol \ H_2O](https://tex.z-dn.net/?f=7.1%20%5C%20mol%20%5C%20H_2O)
There are about 7.1 moles of water.
Answer:
Five ( 5 ) is the correct answer