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s344n2d4d5 [400]
3 years ago
9

Why are fossil fuels important tools for intrepreting the past

Physics
1 answer:
kvv77 [185]3 years ago
6 0
You use them for dem finding of dem artifacts. They tell you about the history and land usage in the past.
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1. Analyze the number line above to describe the motion of the object. Be sure to include starting position, intermediate positi
Colt1911 [192]

1) Distance: 9 m, displacement: +5 m

2) The average speed is 3 m/s

3) The average velocity is +2 m/s

Explanation:

1)

We start by reminding the definitions of distance and displacement:

- Distance: it is the total length of the path covered by an object, regardless of the direction of motion

- Displacement: is the distance in a straight line between the initial position and final position of motion

Let's now analyze the motion represented in the figure:

Initial position: x_0 = -1 m

Intermediate position: x_1 = +6 m

Final position: x_2 = +4 m

Therefore, the distance covered is

distance = |x_1-x_0|+|x_2-x_1|=|+6-(-1)|+|+4-(+6)|=7+2=9 m

While the displacement is:

displacement = x_2 - x_1 = +4 - (-1) = +5 m

2)

The average speed is a scalar quantity defined as

speed=\frac{d}{t}

where

d is the distance travelled

t is the time taken

For the object in this problem,

d = 6 m

t = 2 s

Substituting, we find the average speed:

speed = \frac{6 m}{2 s}=3 m/s

3)

The average velocity is a vector quantity defined as

velocity = \frac{d}{t}

where

d is the displacement

t is the time interval

For the object in this problem,

d = +12 m

t = 6 s

Substituting, we find the average velocity:

velocity=\frac{+12 m}{6s}=+2 m/s

Where the positive sign + indicates the direction of the velocity vector.

Learn more about average speed and average velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

7 0
4 years ago
While spinning in a centrifuge a 70.0 KG astronaut experiences an acceleration of 2.00g, or twice the acceleration due to gravit
alisha [4.7K]
Centripetal acceleration is the force acting on the body who's moving in a circular motion. It is still a force, which according to Newton's Second Law of Motion,

F = ma
F = (70 kg)(2)(9.81 m/s²)
F = 1373.4 N

<em>Thus, the answer is B.</em>
4 0
4 years ago
What force is needed to bring a 1.10 × 10^3 kg car moving at 22 m/s to a halt in 20s?​
Tems11 [23]

Answer:

A very very big hole and some ramps

8 0
3 years ago
A grocery shopper tosses a(n) 9.4 kg bag of rice into a stationary 19.9 kg grocery cart. The bag hits the cart with a horizontal
IRINA_888 [86]

The final speed of the cart and the bag is 2.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the bag and the cart must be conserved before and after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 9.4 kg is the mass of the bag of rice

u_1 = 7.0 m/s is the initial velocity of the bag

m_2 = 19.9 kg is the mass of the cart

u_2 =0 m/s is the initial velocity of the cart (at rest)

v is the final combined velocity of the bag and the cart

Re-arranging the equation and solving for v, we find:  

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(9.4)(7.0)+0}{9.4+19.9}=2.2 m/s

Learn more about momentum here:

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brainly.com/question/6573742  

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#LearnwithBrainly

5 0
3 years ago
A Porsche 944 Turbo has a rated engine power of 217 hp. 30% of the power is lost in the drive train, and 70% reaches the wheels.
shutvik [7]

Answer:

a = 6.53 m/s^2

v = 11.5689 m/s

Explanation:

Given data:

engine power is 217 hp

70 % power reached to wheel

total mass ( car + driver) is 1530 kg

from the data given

2/3 rd of weight is over the wheel

w = 2/3rd mg

maximum force

F = \mu W

we know that F = ma

ma =  \mu (2/3 mg)

a_{max} = 2/3(1.00) (9.8) = 6.53 m/s^2

the new power is p  = 70\% P_[max} = 0.7 P_{max}

P =f_{max} v

0.7P_{max} = ma_{max} v

solving for speed v

v =0.7 \times \frac{P_{max}}{ma_{max}}

v = 0.7 \frac{217 [\frac{746 w}{1 hp}]}{1500 \times 6.53}

v = 11.5689 m/s

7 0
4 years ago
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