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Gekata [30.6K]
3 years ago
15

Hurryyyyy plzzzzzz..........the one in the middle...

Physics
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

Friction force is independent of the direction of the contacting surfaces

Explanation:

It can go any way depending on how much force is being out on it.

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Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor
IgorC [24]

Answer:

A dissipates more power.

Explanation:

  • In a series circuit, the current is the same at any point in it.
  • The power dissipated in any resistor follows Joule's law, as follows:

        P = I^{2} * R

  • So, for a given current, the power is directly proportional to the resistance of the resistor.
  • In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.
8 0
3 years ago
On my bike I was able to travel 40 miles in one hour from this information we can determine the bikes
valentinak56 [21]
You have a distance and a time so you can work out the bikes speed which would be distance/time so 40mph.
4 0
3 years ago
Why are there shadows?
Deffense [45]
Shadows are formed when an opaque object or an object that doesn't allow light to pass through is in the way or infront of etc. a source of light.
6 0
3 years ago
Read 2 more answers
Merry-go-rounds are a common ride in park playgrounds. The ride is a horizontal disk that rotates about a vertical axis at their
Vera_Pavlovna [14]

Answer:

A = 2.36m/s

B = 3.71m/s²

C = 29.61m/s2

Explanation:

First, we convert the diameter of the ride from ft to m

10ft = 3m

Speed of the rider is the

v = circumference of the circle divided by time of rotation

v = [2π(D/2)]/T

v = [2π(3/2)]/4

v = 3π/4

v = 2.36m/s

Radial acceleration can also be found as a = v²/r

Where v = speed of the rider

r = radius of the ride

a = 2.36²/1.5

a = 3.71m/s²

If the time of revolution is halved, then radial acceleration is

A = 4π²R/T²

A = (4 * π² * 3)/2²

A = 118.44/4

A = 29.61m/s²

7 0
3 years ago
A rocket is fired at 100 m/s at an angle of 37, how many seconds did it take to get to the top?
Kobotan [32]

Answer:

6.14 s

Explanation:

The time the rocket takes to reach the top is only determined from its vertical motion.

The initial vertical velocity of the rocket is:

u_y = u sin \theta = (100)(sin 37^{\circ})=60.2 m/s

where

u = 100 m/s is the initial speed

\theta=37^{\circ} is the angle of launch

Now we can apply the suvat equation for an object in free-fall:

v_y = u_y +gt

where

v_y is the vertical velocity at time t

g=-9.8 m/s^2 is the acceleration of gravity

The rocket reaches the top when

v_y =0

So by substituting into the equation, we find the time t at which this happens:

t=-\frac{u_y}{g}=-\frac{60.2}{-9.8}=6.14 s

7 0
3 years ago
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