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lys-0071 [83]
2 years ago
14

If an amount of heat Q is needed to increase the temperature of a solid metal sphere of diameter D from 4°C to 7°C, the amount o

f heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is
Physics
1 answer:
Hitman42 [59]2 years ago
7 0

Answer:

Q = c M ΔT      where c is the heat capacity and M the mass present

Q2 / Q1 = M2 / M1    since the other factors are the same

M = ρ V     where ρ is the density

M = ρ Π (d / 2)^2           where d is the diameter of the sphere

M2 / M1 = (2 D/2)^2 / (D/2)^2 = 4

It will take 4Q heat to heat the second sphere

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you push a block of 50kg with a force of 400 N over a distance of 8m. How much kinetic energy does the box gain?
MatroZZZ [7]

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160000

Explanation:

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2 years ago
A rocket is launched from atop a 101 foot cliff with an initial velocity of 116 ft/s.
Katen [24]

Answer:

A. 16t2 -116t -101=0 B. 8.0s

Explanation:

Known parameters from the question:

Height of Cliff,h0 = 101ft

Velocity of rocket ,v= 116ft/s.

1.Substituting the above to the above formula we have;

h(t) = -16t2 + vt + h0

Since h(t) =0, it means the rocket is falling towards the ground, when it gets to the ground when it's at rest the height h(t) = 0m

{Note the rocket is launched from the height of the Cliff so that would be the initial height of the rocket,h0}

2.Substituting into h(t) = -16t2 + vt + h0

We have;

0 = -16t2 + 116t + 101=> 16t2 -116t -101=0

Using formula method for solving quadratic equation we have;

t = -(-116)+_√[(-116)^2 -( 4× 16 ×-101]/ (2× 16)

t = [116 +_(141.1382)]/32

t = (116 -141.1382)/32 or (116 +141.1382)/32

-0.786s or 8.036s

-0.8s or 8.0s to the nearest tenth.

Now time cannot be negative in real life situation hence the time is 8.0s

Note : the general equation of a quadratic equation with variable t is given below;

at2 + bt + c=0

Formula method for quadratic equation is :

t =( -b+_√[(b^2 -( 4× a×c)] ) / (2× a)

6 0
3 years ago
A truck travels up a hill with a 5.4° incline. The truck has a constant speed of 25 m/s. What is the horizontal component of the
goldenfox [79]

Answer:

v_{x}=24.88m/s

v_{y}=2.35m/s

Explanation:

Knowing that the truck travels up a hill with a 5.4º incline

The horizontal component of the truck's velocity is:

v_{x}=vcos\beta=(25m/s)cos(5.4)=24.88m/s

The vertical component of the truck's velocity is:

v_{y}=vsin\beta=(25m/s)sin(5.4)=2.35m/s

8 0
3 years ago
What is the mass of an object if a force of 34 N produces an acceleration of 4 m/s^2?
Paha777 [63]
F=ma

F/a=m

34/4 =8.5

8.5 kilograms
8 0
3 years ago
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