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d1i1m1o1n [39]
2 years ago
5

The zeros of the function f(x) =(x+2) to the second power minus 5

Mathematics
1 answer:
pashok25 [27]2 years ago
8 0
(x+2)^2-5=0\\
(x+2)^2=5\\
x+2=-\sqrt5 \vee x+2=\sqrt5\\
x=-2-\sqrt5 \vee x=-2+\sqrt5
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Answer:

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Step-by-step explanation:

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Hint: | Move terms with n to the left hand side.

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Hint: | Combine like terms in n - 4 n.

n - 4 n = -3 n:

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Hint: | Look for the difference of two identical terms.

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Divide both sides of -3 n = 15 by -3:

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n = 5/(-1)

Hint: | Simplify the sign of 5/(-1).

Multiply numerator and denominator of 5/(-1) by -1:

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