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3 years ago

The zeros of the function f(x) =(x+2) to the second power minus 5

Mathematics

1 answer:

pashok25 [27]3 years ago

8 0

$(x+2)^2-5=0\\
(x+2)^2=5\\
x+2=-\sqrt5 \vee x+2=\sqrt5\\
x=-2-\sqrt5 \vee x=-2+\sqrt5$

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P(x)=(x-2)(x-4)(x-5)

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The constants of a polynomial is the term that has no variable attached to it.

<h3>The constant term</h3>

To determine the constant, we simply multiply the constant term in each factor of the polynomial.

So, we have:

<h3 /><h3>Polynomial P(x) = (x-2)(x-4)(x-5)</h3>

$Constant = -2 \times -4 \times -5$

$Constant = -40$

Hence, the constant is -40

<h3>Polynomial P(x) = (x-2)(x-4)(x+5)</h3>

$Constant = -2 \times -4 \times 5$

$Constant = 40$

Hence, the constant is 40

<h3>Polynomial P(x) =1/2(x-2)(x-4)(x+5)</h3>

$Constant = \frac 12 \times -2 \times -4 \times 5$

$Constant = 20$

Hence, the constant is 20

<h3>Polynomial P(x) = 5(x-2)(x-4)(x+5)</h3>

$Constant = 5 \times -2 \times -4 \times 5$

$Constant = 200$

Hence, the constant is 200

$Constant = -5 \times -2 \times -4 \times 5$

$Constant = -200$

Hence, the constant is -200

Read more about polynomials at:

brainly.com/question/2833285

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