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3 years ago

5

The zeros of the function f(x) =(x+2) to the second power minus 5

1 answer:

pashok25 [27]3 years ago

8 0

$(x+2)^2-5=0\\
(x+2)^2=5\\
x+2=-\sqrt5 \vee x+2=\sqrt5\\
x=-2-\sqrt5 \vee x=-2+\sqrt5$

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